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svlad2 [7]
3 years ago
14

Line segment AB is divided by point C in the ratio 1:2. Point A is at (-6, 6) and point C is at (2, 4). What are the coordinates

of point B?
Mathematics
1 answer:
grandymaker [24]3 years ago
8 0

9514 1404 393

Answer:

  B(10, 2)

Step-by-step explanation:

The division by point C means ...

  B -C = 2(C -A)

  B = 3C -2A . . . . . add C and simplify

  B = 3(2, 4) -2(-6, 6) = (3·2 -2(-6), 3·4 -2(6))  . . . .  fill in the coordinate values

  B = (6+12, 12-12)

  B = (18, 0)

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Find the missing length
shutvik [7]
The small triangle and big triangle are similar - this means they have the same angles. So, if you know the ratio of a side of the big triangle (12) to a side of the small triangle inside it (4), you know the ratio of the other sides. In this case, the side ratio (small to big triangle) is 1/3. Thus, the missing side length is 18/3=6.
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7 0
4 years ago
If f(a) = 2a ^ 3 + 3a ^ 2 + 5 , find f(- 2)
UkoKoshka [18]
<h2>Answer: 1</h2>

Step-by-step explanation:

Just plug in -2 anywhere you see an <u>a</u>

f(a)=2a^3+3a^2+5\\f(-2)=2(-2)^3+3(-2)^2+5\\f(-2)=2(-8)+12+5\\f(-2)=-16+12+5\\f(-2)=1

8 0
2 years ago
Read 2 more answers
On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and
Oduvanchick [21]

Given:

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5 0
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alexdok [17]
The answer to this question is....

6 0
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Answer:

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3 years ago
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