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Otrada [13]
1 year ago
14

When constructing a perpendicular bisector why must the compass opening be greater than 1/2.

Mathematics
1 answer:
muminat1 year ago
4 0

It is critical to open a compass with over half the way in order for the arcs formed to meet for perpendicular bisector.

<h3>What is perpendicular bisector?</h3>

A perpendicular bisector would be a line that cuts a line segment in half and forms a 90-degree angle at the intersection point. In other words, a perpendicular bisector separates a line segment now at midpoint, forming a 90-degree angle.

Now, consider an example;

When you wish to build a perpendicular line on a line segment, like line AB, you do the following;

  1. Set the compass on a radius more than half the length of the line AB.
  2. Using A as your center, draw an arc above and below line AB.
  3. With the same radius and B as our center, draw additional arcs on top or below line AB to join a first arcs on the both side of the line.
  4. Join the two arc intersections to cut line AB at M.

A line AB appears to be bisected perpendicularly as a result. The arcs would not have met if the compass is opened less than half way down line AB.

To know more about perpendicular bisector, here

brainly.com/question/7198589

#SPJ4

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In quadrilateral PQRS, the coordinates are (0,0), R(a +c, b), and S(a, b). How can you use coordinate geometry to show that the
aliina [53]

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A technique that can help you to know if two straight lines are perpendicular is is you find their slopes. Let's say the slope of line 1 is m1 and the slope of line 2 is m2. If m1*m2 yields a product of -1, then the lines are perpendicular. This is because if m1 is the negative reciprocal of m2, the lines are perpendicular. But if m1=m2, the lines are parallel, meaning they don't intersect at all.

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6 0
3 years ago
What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?
11111nata11111 [884]

Answer:

R' = (-1,-0.5)

Step-by-step explanation:

See attachment for complete question.

From the attachment:

P = (-3,-3)

R = (1,2)

Dilation:

D_{(0.5,P)}

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

R = (1-(-3),2-(-3))

R = (1+3,2+3)

R = (4,5)

Next, apply dilation factor 0.5

R' = R * 0.5

R' = (4,5) * 0.5

R' = (4* 0.5,5* 0.5)

R' = (2,2.5)

Lastly, measure R' from the origin by adding the coordinates of P to R'

R' = (2+(-3),2.5+(-3))

R' = (2-3,2.5-3)

R' = (-1,-0.5)

6 0
2 years ago
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