Answer:
the answer is the first one [3 -12 15 -21]
Step-by-step explanation:
Because 3 times 1 = 3, 3 times -4 = -12, 3 times 5=15, 3 times 7 = -21
because they are in order to get a negative one of them have to be a negative if they both of them where negative it would be positive.
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If there are 13 letters typed, the probability that no letters will be repeated can be found to be 1.05 x 10⁻²⁰
<h3>How to find the probability no letters are repeated?</h3>
First, find the number of possibilities of 13 letters from 26 letters in the alphabet as:
= 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26 x 26
= 6.156 x 10³⁶ possibilities
If the numbers are not to be repeated then the possibilities are:
= 26 x 25 x 24 x 23 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14
= 64764752532480000 possibilities
The probability that no letters are repeated is:
= 64764752532480000 / 6.156 x 10³⁶
= 0.0000000000000000000105
= 1.05 x 10⁻²⁰
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Let's do the bracket part first,
and solve further as shown,
Let x represent the larger number.
1/(x -28) +4/x = 1/6
Multiplying by the product of denominators, we have
6x +24(x -28) = x(x -28)
In standard form, this is
x^2 -58x +672 = 0
(x -42)(x -16) = 0
The two numbers are (-12 and 16) or (14 and 42).
