Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8
Answer: The expression that represents Meg's finishing time in June is "y - 10".
The problem started with Meg running in April. She had a time in April and we called it "y".
Now, Meg ran again in June. In June, she did 10 seconds faster. So it makes since that we need to subtract 10 from her April time, "y". Therefore, the expression is simply "y - 10".
Answer:
200 in.
Step-by-step explanation:
1250/75=5000/300=50/3 simplification
50*12=600 conversion to inches
600/3=200 simplification
This is a problem of Standard Normal distribution.
We have mean= 12 grams
Standard Deviation = 2.5 grams
First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:
So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808
Thus, the <span>
probability that the strawberry weighs less than 8.5 grams is 0.0808</span>
Answer:
(- 1, 1 )
Step-by-step explanation:
Given the 2 equations
2x - y = - 3 → (1)
x + y = 0 → (2)
Adding the 2 equations term by term will eliminate the term in y, that is
3x = - 3 ( divide both sides by 3 )
x = - 1
Substitute x = - 1 into either of the 2 equations and solve for y
Substituting into (2)
- 1 + y = 0 ( add 1 to both sides )
y = 1
Solution is (- 1, 1 )
