8 months ago

What are the zeroes of f(x) = x2 + 5x + 6? (1 point) x = −2, −3 x = 2, 3 x = −2, 3 x = 2, −3

Mathematics

1 answer:

Strike441 [17]8 months ago

5 0

Answer:

$x = - 2 - \sqrt{2i} \: \: - 2 + \sqrt{2i}$

Step-by-step explanation:

$1. \: x - {x}^{2} - 5x - 6 = 0 \\ 2. \: - 4x - {x}^{2} - 6 = 0 \\ 3. \: x = \frac{4 + 2 \sqrt{2i} }{ - 2} \: \: \frac{4 - 2 \sqrt{2i} }{ - 2} \\ 4. \: x = - 2 - \sqrt{2i} \: \: - 2 + \sqrt{2i}$

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If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2