Question

What are the zeroes of f(x) = x2 + 5x + 6? (1 point) x = −2, −3 x = 2, 3 x = −2, 3 x = 2, −3

Answer 1

Answer:

$x = - 2 - \sqrt{2i} \: \: - 2 + \sqrt{2i}$

Step-by-step explanation:

$1. \: x - {x}^{2} - 5x - 6 = 0 \\ 2. \: - 4x - {x}^{2} - 6 = 0 \\ 3. \: x = \frac{4 + 2 \sqrt{2i} }{ - 2} \: \: \frac{4 - 2 \sqrt{2i} }{ - 2} \\ 4. \: x = - 2 - \sqrt{2i} \: \: - 2 + \sqrt{2i}$