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3 years ago

Is the equation y = x^2 -6 linear?

Mathematics

2 answers:

BARSIC [14]3 years ago

6 0

Answer:

i don't think so

Step-by-step explanation:

IrinaK [193]3 years ago

4 0

Answer:

Step-by-step explanation:

for the equation y=x^2 -6 the line is curved and both points are facing up. A linear pair has to be straight. Therefore, this equation isn't linear

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A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder

Sedaia [141]

Initial speed of the skateboard (u) = 0 m/s (Starts from rest)

Acceleration of the skateboard (a) = 2 m/s²

Time taken by the skateboard (t) = 2s

By using equation of motion, we get:

$\bf \longrightarrow v = u + at \\ \\ \rm \longrightarrow v = 0 + 2 \times 2 \\ \\ \rm \longrightarrow v = 4 \: m {s}^{ - 1}$

$\therefore$ Final speed of the skateboard(v) = 4 m/s

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3 years ago

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V125BC [204]

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3 years ago

What's 30 inches decreased by 30%

Elanso [62]

Answer:

Step-by-step explanation:

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3 years ago

Write the slope-intercept form of the equation of the line that passes thrqugh (-4, -3) and is

Zielflug [23.3K]

Answer:

Step-by-step explanation:

Equation of the line y = mx + c

The new line is perpendicular to 2x - 3y = -5

- 3y = - 5 - 2x

3y = 2x + 5

y = $\frac{2x}{3} + \frac{5}{3}$

Since the lines are perpendicular to each other : $m_{1} . m_{2} = -1$

where $m_{1} \ slope \ of \ the \ given \ line \ and \ m_{2} \ slope \ of \ the \ new \line\\$ .

Slope of the given line

$m_{1} = \frac{2}{3}$

Slope of the new line

$\\\frac{2}{3}.m_{2} = -1\\ m_{2} = -1 . \frac{3}{2} = \frac{-3}{2}$

The equation to the new line passing through (-4, -3) and perpendicular to 2x - 3y = -5

$(y - y_{1}) = m_{2}(x-x_{2} )\\\\(y - (-4)) = \frac{-3}{2}(x - (-3)) \\\\(y + 4) = \frac{-3}{2} (x+ 3)\\\\2(y +4) = -3(x+3)\\\\2y + 8 = -3x -9 \\\\2y = -3x - 9 -8\\\\y = \frac{-3x}{2} - \frac{17}{2}$

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3 years ago

Make 6 prime number using 1,2,3,4,5,6,7,8,9

Crazy boy [7]

Answer:

13,67,29,17,19,23

Step-by-step explanation:

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3 years ago

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