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2 years ago

Caroline bought snacks for her team's practice. She bought a bag of oranges for $2.21

Mathematics

1 answer:

Vanyuwa [196]2 years ago

3 0

The equation which can be used to determine x, how much each bottle of juice cost is 9.38 = 2.21 + 3x

<h3>How to represent an equation?</h3>

She bought a bag of oranges for $2.21 and a 3-pack of juice bottles.

The total cost before tax was $9.38.

Let

x = number of bottle of juice.

Hence,

The equation which can be used to determine x, how much each bottle of juice cost is as follows:

Therefore,

9.38 = 2.21 + 3x

Hence,

9.38 = 2.21 + 3x

9.38 - 2.21 = 3x

7.17 = 3x

x = 7.17 / 3

x = 2.39

learn more on equation here: brainly.com/question/21583215

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A direct variation function contains the points (-9, -3) and (-12,4). Which equation represents the function?

Triss [41]

Answer:

$y = -\frac{7x}{3} - 24$

Step-by-step explanation:

We can model this function using the equation of a line:

$y = ax + b$

Where a is the slope of the line and b is the y-intercept.

To find the values of a and b, we can use the two points given:

(-9, -3):

$-3 = a * (-9) + b$

$-9a + b = -3$

(-12, 4):

$4 = a * (-12) + b$

$-12a + b = 4$

If we subtract the second equation from the first one, we have:

$-12a + b - (-9a + b) = 4 - (-3)$

$-12a + 9a = 4 + 3$

$-3a = 7$

$a = -7/3$

Then, finding the value of b, we have:

$-12a + b = 4$

$28 + b = 4$

$b = -24$

So the equation is:

$y = -\frac{7x}{3} - 24$

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3 years ago

5(y+2/5)=-13 need help asap rocky

Gwar [14]

Answer:

y=-3

Step-by-step explanation:

first distribute then solve for y

5y+2=-13

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3 years ago

Read 2 more answers

Question below

Ksivusya [100]

Answer:

$m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]$

Step-by-step explanation:

Calculate the value of m

Given:

$3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]$

Therefore:

$\implies 3=\dfrac{2}{3}m$

$\implies m=3 \times \dfrac{3}{2}$

$\implies m=\dfrac{9}{2}$

Calculate the value of H

Given:

$\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)$