A bag of baseballs cost 9.99 dollars and each bag contains 6 baseballs. if the baseballs were sold individually, how much would
1 answer:
The price of each ball in a baseball bag would be 1.665 dollars
It is given that,
The cost price of a bag of baseball bag = 9.99 dollars
The number of balls in each bag = 6 baseballs
Now, we need to find the cost of one baseball if it were to sold individually
To find the cost of one quantity out of a bunch we divide the bunch price with the number of quantities in the bunch
Here, in this case
The cost price of each ball =
=
= 1.665 dollars
Hence, the price of each ball in a baseball bag would be 1.665 dollars
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Answer:
The answer is "7"
Step-by-step explanation:
Please find the complete question and the solution file in the attachment.
remainder=7
Answer: See the table below (attached image)
- SSb = 2345
- SSt = 5639
- DFb = 5
- DFw = 54
- MSb = 469
=============================================================
Explanation:
I'll start at the right side of the table and work my way toward the left side.
I recommend you have a one way ANOVA formula sheet handy. Such a formula sheet should be located somewhere in the ANOVA chapter of your stats textbook, or toward the appendix section. There are various free online resources to search out as well.
On that formula sheet you should find that
(MSb)/(MSw) = F
where MSb and MSw are the mean squares between and within respectively.
We can find the value of MSb like so
(MSb)/(MSw) = F
MSb = F*MSw
MSb = 7.682*61
MSb = 468.602
This rounds to 469, so we'll go with MSb = 469. The reason I'm rounding is that I've done a similar problem in the past, and the computer system wanted me to round to the nearest whole number. Also, note how every value of the table given to us consists of whole numbers. Of course, your teacher may want you to keep the decimal value instead. So I would ask for clarification if possible.
Since we're going with MSb = 469, this means 469 goes in the last box of row 1.
-----------------------------------------------
Now go back to your reference sheet to locate this formula
MSw = (SSw)/(DFw)
Rearrange this formula to get
DFw = (SSw)/(MSw)
Now plug in the values we have from the table to find,
DFw = (SSw)/(MSw)
DFw = (3294)/(61)
DFw = 54 which goes in the box found in the second row.
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Now recall that
DFb + DFw = df
where DFb is the degrees of freedom between and df is the total degrees of freedom, which in this case is 59.
Using the table and the value we found earlier, we can see that,
DFb = df - DFw
DFb = 59 - 54
DFb = 5 this goes in the second box of row one (ie above the 54).
-----------------------------------------------
Also on your formula sheet, you should see something like
MSb = (SSb)/(DFb)
where each lowercase 'b' stands for "between", and the other abbreviations are what were discussed earlier.
That formula rearranges into
SSb = (DFb)*(MSb)
Then we can use the values we calculated earlier to find
SSb = (DFb)*(MSb)
SSb = (5)*(469)
SSb = 2345 this goes in the first box of row one.
----------------------------------------------
Lastly, computing the total sum of squares (SSt) will simply involve us adding the two SSb and SSw values to get
SSt = SSb + SSw
SSt = 2345 + 3294
SSt = 5639 this goes in the box of row three.
----------------------------------------------
To summarize, we have these values to fill into the table
- SSb = 2345
- SSt = 5639
- DFb = 5
- DFw = 54
- MSb = 469
where we have these abbreviations
- SS = sum of squares
- MS = mean square
- DF = degrees of freedom
- b = between
- w = within
Check out the diagram below for the filled in values.
To summarize the formulas used, we basically have the template of
MS = (SS)/(DF)
for both between and within. And we also have the formula F = (MSb)/(MSw). So effectively, the values are found through various division formulas or rearrangements of such. I'm referring to working along any given row. For any given column, we add up the values to get the totals, though that of course does not apply to MS or F.
Admittedly, ANOVA tables and concepts can be confusing because there are a lot of variables and steps going on. But once you get used to it, it's not too bad if you can see how the patterns are emerging (the division and additions I was referring to earlier).
