Answer:
C. 7 - 3 = 4
Step-by-step explanation:
Given
![Dataset: 3, 3, 4, 5, 6, 7, 10](https://tex.z-dn.net/?f=Dataset%3A%203%2C%203%2C%204%2C%205%2C%206%2C%207%2C%2010)
Required
The IQR
The IQR is calculated using:
![IQR = Q_3 - Q_1](https://tex.z-dn.net/?f=IQR%20%3D%20Q_3%20-%20Q_1)
Where:
Median of the upper ![half](https://tex.z-dn.net/?f=half)
Median of the lower ![half](https://tex.z-dn.net/?f=half)
The dataset has 7 values, so the median is: (7 + 1)/2 =8/2 = 4th position.
Split to two, we have:
![Lower \to 3, 3, 4](https://tex.z-dn.net/?f=Lower%20%5Cto%203%2C%203%2C%204)
![Median \to 5](https://tex.z-dn.net/?f=Median%20%5Cto%205)
![Upper \to 6, 7, 10](https://tex.z-dn.net/?f=Upper%20%5Cto%206%2C%207%2C%2010)
The lower half has 3 data; So, the median is the 2nd position.
Hence:
![Q_1 = 3](https://tex.z-dn.net/?f=Q_1%20%3D%203)
The upper half has 3 data; So, the median is the 2nd position.
Hence:
![Q_3 = 7](https://tex.z-dn.net/?f=Q_3%20%3D%207)
So, the IQR is:
![IQR = Q_3 - Q_1](https://tex.z-dn.net/?f=IQR%20%3D%20Q_3%20-%20Q_1)
![IQR = 7 - 3](https://tex.z-dn.net/?f=IQR%20%3D%207%20-%203)
![IQR = 4](https://tex.z-dn.net/?f=IQR%20%3D%204)
Answer: Additional day is associated with a production of 26 units
Steps:
130 units ---- 5 days
650units ---- 25 days
which shows this is a linear relationship (130 units x 5 = 650 units)
So we can divide the increase (650-130) = 520 by 20 days to get the increase per 1 day: 520 units /20 days = 26 units/day
Answer:
12
Step-by-step explanation:
560-500=60
60/500*100=12