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leonid [27]
3 years ago
6

On average, Matt's Manufacturing Company produces 130 units in five working days and 650 units in twenty-five working days. In a

linear model of this situation, which of the following statements applies?
Mathematics
1 answer:
Paul [167]3 years ago
6 0

Answer: Additional day is associated with a production of 26 units

Steps:

130 units ---- 5 days

650units ---- 25 days

which shows this is a linear relationship (130 units x 5 = 650 units)

So we can divide the increase (650-130) = 520 by 20 days to get the increase per 1 day: 520 units /20 days = 26 units/day

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den301095 [7]
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8 0
3 years ago
Which solid has a greater volume
Triss [41]

Answer:

The volume of cylinder and the volume of a cone, have equal volume measurements. So, the answer is C).

Step-by-step explanation:

Cylinder:

-Use the formula for the volume of a cylinder. Use both the radius and height for the formula in order to solve and get the volume:

V = \pi r^2 h

V = \pi 2^2 6

-Solve:

V = \pi 2^2 6

V = \pi \times 2^2 \times 6

V = \pi \times 4 \times 6

V = \pi \times 24

V = 24\pi \approx 75.39

--------------------------------------------------------------------------------------------------------

Cone:

-Use the formula for the volume of a cone and the radius and height for the formula and solve the formula to get the volume:

V = \frac{1}{3} \pi r^2h

V = \frac{1}{3} \pi 3^28

-Solve:

V = \frac{1}{3} \pi 3^28

V = \frac{1}{3} \times \pi \times 3^2 \times 8

V = \frac{1}{3} \times \pi \times 9 \times 8

V = \frac{1}{3} \times \pi \times 72

V = \frac{1}{3} \pi \times 72

V = 24\pi \approx 75.39

-So, according to the volume of a cylinder and the volume of a cone, They both have the same volume.

Cylinder: 75.39 ft^3

Cone: 75.39 ft^3

5 0
3 years ago
HELP ASAP!!!!!!!!!! in triangle ABC, m
Mashutka [201]

Answer:

I think it is C

Step-by-step explanation:

3 0
3 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

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