All categories

3 years ago

8. The perimeter of Brianna's rectangular garden is 100 feet. The length of the garden is 1.5 times longer than

Mathematics

1 answer:

NeX [460]3 years ago

7 0

Answer:

Step-by-step explanation:

The perimeter of Brianna's rectangle garden is 100 feet. The length of the garden is 1.5 longer than the width

You might be interested in

PLEASEEEEEEEEEE HELPPPPPPPPPPP

ankoles [38]

Answer:

I would just guess, but if i were to actually think about it, i would think C. I hope it helps, and blame it on me if you fail.

Step-by-step explanation:

8 0

3 years ago

Part 1: Use the information provided to write the standard form equation of each circle. Please show the work.

dusya [7]

Answer:

1. (x + 2)² + (y - 9)² = 64

2. (x + 6)² + (y - 9/2)² = 100

3. (x - 15)² + (y + 10)² = 1

Step-by-step explanation:

Equation of a circle:

(x - h)² + (y - k)² = r²

1. Center: (-2, 9), Radius: 8

(x - (-2))² + (y - 9)² = 8²

(x + 2)² + (y - 9)² = 64

2. Center: (-6, 9/2), Radius: 10

(x - (-6))² + (y - (9/2))² = 10²

(x + 6)² + (y - 9/2)² = 100

3. Center: (15, -10), Radius: 1

(x - 15)² + (y - (-10))² = 1²

(x - 15)² + (y + 10)² = 1

4 0

3 years ago

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

4 0

3 years ago

What is the slope of the line that contains the point (13,-2) and (3,-2)

ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

Solution:

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

The slope of line is given as:

$m = \frac{y_2-y_1}{x_2-x_1}$

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

$(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)$

Substituting the values in formula, we get,

$m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0$

Thus the slope of line is 0

3 0

3 years ago

Use the law of sines to find what Angle R is:

stich3 [128]

Answer:

Step-by-step explanation:

So, according to the law of Sines, we have

$\frac{Sin(A)}{a} = \frac{Sin(b)}{b}$

In our case, we have S and R, so...

$\frac{Sin(S)}{s} = \frac{Sin(R)}{r}$

And we want to isolate R...

$r = sin^{-1} (\frac{Sin(S) * r}{s} ) = sin^{-1} (\frac{Sin(52) * 32}{26} ) = 75.90$

the angle of R is then 75.90 degrees.

5 0

4 years ago