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4 years ago

A walking trail through a forest preserve is 34,215 meters in length .What is length in kilometers of the trail ?

Mathematics

2 answers:

Lyrx [107]4 years ago

7 0

For this case, the first thing you should do is take into account the following unit conversion:

$1 Km = 1000m$

Therefore, we must apply the conversion to the given amount.

We have then:

$34215m(\frac{1Km}{1000m})=34.215Km$

Answer:

The length in kilometers of the trail is 34.215Km.

Alika [10]4 years ago

4 0

34.215 kilometers you move the decimal to the left three places because Kilo means 1000 and there are 3 zeros in 1000. you move left because Kilometer is bigger than meter.

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mrs_skeptik [129]

Answer:

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Step-by-step explanation:

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3 years ago

What is 3,482,000,000 in scientific notation?

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4 years ago

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Suppose y varies directly as x², and y = 160 when x = 4. Find y when x = 6.

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Finding the constant of proportionality :

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2 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2X + Y = A and 3X - 4Y = B.

Then you can eliminate Y by taking the sum

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==> X = (4A + B)/11

Similarly, you can eliminate X by using

-3A + 2B = -3 (2X + Y) + 2 (3X - 4Y) = -11Y

==> Y = (3A - 2B)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

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