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Lostsunrise [7]
3 years ago
5

Three times the difference of 5 and a number gives 30. Find the number.​

Mathematics
1 answer:
Temka [501]3 years ago
5 0

Answer:

15

Step-by-step explanation:

we need to write the equation. I came up with....

3(5 - x) = 30

so take the 3 away from the 30. I think your not supose to do the 3 because it out of the ( ). the opppisite of multiplication is division. so...

3 divided by 30 =10

rewrite

(5 - x) = 10

take the 5 away. the oppisite of subbtraction is addition.

5 + 10 = 15

check your; plug in x

3(5 - 15) = 30  This equation looks true!

Hope this helped! Please mark as brainliest! Thanks

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The function f(x) is given by the set of ordered pairs.
Lana71 [14]

The equation that is true and one that matches the set of ordered pairs of functions is option C. f (0) = 6

<h3>What is the equation about?</h3>

Note that a function can be made to be a given set of ordered pairs such as the ordered pairs (2,4), (3,5), (4,6)  can have  input functions of ​​(as domain) 2,3,4 and output functions of ​​(as range) of 4,5,6.

So when you see the ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2, –1)} one can see that the option that matches to the set of ordered pairs of functions above is f (0) = 6 value x = 0, f (x) = y = 6, ordered pairs (0.6)

See full question below

The function f (x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2, –1)}:Which equation is true?

f(-10)=1

f(2)=-10

f(0)=6

f(1)=-10

The answer choices are :

f (-10) = 1 values ​​x = -10, f (x) = y = 1, ordered pairs (-10,1)

f (2) = - 10 values ​​x = 2, f (x) = y = -10, ordered pairs (2, -10)

f (0) = 6 value x = 0, f (x) = y = 6, ordered pairs (0.6)

f (1) = - 10 values ​​x = 1, f (x) = y = -10, ordered pairs (1, -10)

Learn more about ordered pairs from

brainly.com/question/6200217

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Answer:

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What are the roots of the equation x2 - 5x + 6 = 0?
Alenkasestr [34]

The answer is

B. -2 and 3

Step-by-step explanation :

Given the expression

x²- 5x + 6 = 0

Firstly we need to find two numbers that when multiplied will give us the constant term 6, and when added will give us the 2nd term 5

These numbers are 3 and 2

Substituting 2x +3x for 5x

x²- (2x+3x)+ 6 = 0

x²-2x-3x+6=0

(x²-2x)-(3x+6)=0

Factoring we have

x(x-2)-3(x-2)=0

x-3=0, x-2=0

x=3, x= 2

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