-30=q-10+11q Pls help me answer this

Mathematics

1 answer:

Leno4ka [110]3 years ago

5 0

Combine q terms
-30 = 12q - 10
Add 10 to both sides
-20 = 12q
Simplify
Q = -5/3

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An arc 28 cm is cut from a circle of radius 15 cm. Find the angle of the sector formed by this arc.

Nutka1998 [239]

Answer:

$\displaystyle \frac{28}{15}\; \text{radians}$ , which is approximately $107^{\circ}$ .

Step-by-step explanation:

In a given circle, the angle of a sector is proportional to the length of the corresponding arc:

$\displaystyle \frac{\text{angle of sector $1$}}{\text{angle of sector $2$}} = \frac{\text{length of arc of sector $1$}}{\text{length of arc of sector $2$}}$ .

For the circle in this question, $r = 15\; \rm cm$ , and the circumference would be:

$2\, \pi \, r = 30\, \pi\; \rm cm$ .

The full circle itself is like a sector with an angle of $2\, \pi$ , with the arc length equal to the circumference of the circle.

$\displaystyle \frac{\text{angle of sector}}{\text{angle of full circle}} = \frac{\text{length of arc of sector}}{\text{circumference of circle}}$ .

$\displaystyle \frac{\text{angle of sector}}{2\,\pi\; \rm rad} = \frac{28\; \rm cm}{30\, \pi\; \rm cm}$ .

Rearrange the equation to find the angle of the sector:

$\begin{aligned} & \text{angle of sector} \\ =\; & (2\,\pi\; \rm rad) \cdot \frac{28\; \rm cm}{30\, \pi\; \rm cm} \\ =\; & \frac{28}{15}\; \rm rad\end{aligned}$ .

In other words, the angle of this sector would be $\displaystyle \frac{28}{15}\; \rm rad$ . Multiply that measure in radians by $\displaystyle \frac{360^{\circ}}{2\,\pi\; \rm rad}$ to find the value of the angle measured in degrees: