Answer:
19.9 miles
Step-by-step explanation:
In this problem we have:
is the distance travelled during the 1st day
is the distance travelled during the 2nd day
is the distance travelled during the 3rd day
is the distance travelled during the 4th day
We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

Which can be rewritten using the general formula:

This means that

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

So, the distance travelled on the 7th day is 19.9 miles.
Answer:
$10
Step-by-step explanation:
0.05x=0.50
x=10
Your picture doesn’t load
Well when she hits the water h=0 so
2t^2-t-6=0 factor
2t^2-4t+3t-6=0
2t(t-2)+3(t-2)=0
(2t+3)(t-2)=0, since t>0
t=2 seconds...
However it should be noted that h(t)=-2t^2+t+6 implies that
v(t)=dh/dt=-4t+1 and
a(t)=dv/dt=-4
Since this is a free fall equation, this would suggest that the acceleration due to gravity is -4, whether that is supposed to be -4ft/s^2 or -4m/s^2, it certainly is not on this planet! :D If it is -4ft/s^2 it could be on the Moon or if it is -4m/s^2 it could be on Mars.
1) Striangle = 1/2 * (12-8) * 4 = 1/2 * 4 * 4 = 8 km^2
2) Srectangle = 4 * 8 = 32 km^2
3) Sfigure = 8 + 32 = 40 km^2
Number C