<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
Given that diameter of the base of the cylinder = 8 ft
Given that height of the cylinder = 6 ft
We have to find the surface area of the cylinder in terms of pi.
So we need to use formula of surface area of the cylinder which is
where h= height = 6
r= radius = diameter/2 = 8/2 = 4
Now plug these values into above formula
Hence final answer is
square ft
<span>Interest=principle x rate x time (in years)
so putting values so
Interest=7500 (.042)(2)
so
Interest=630
7500+630=8130
Interest=500 (.071)(4)
Interest=142
500+142=64
hope it helps</span>
Here we go ~
The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :
Now we have to calculate the descent in 3.5 minutes ~
So, the airplane descends 2172.41 feels in three and a half minutes ~
Answer:
(6,1)
Step-by-step explanation:
after switching the equations from y=mx+b, graph both equations. you will see that the point of intersection is (6,1)
