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vladimir2022 [97]
2 years ago
13

By paying $1500 cash and the balance is equal monthly payments, how many months would it take to pay for a car costing $12,495?

Mathematics
1 answer:
Elden [556K]2 years ago
4 0

The monthly installments need to be paid is $10995.

To determine the number of months needed to pay off the remaining balance. We need to know the monthly installment.

<h3>What is installments?</h3>

When you get an installment loan, you get the money you borrowed or the item you bought right away.

  • You pay it off in installments, which are regularly scheduled payments that may include interest.
  • For a set number of months, or years, you generally owe the same amount on every installment.
  • When the loan is fully repaid, the account is permanently closed.

Now, as per the question;

Amount paid in cash = $1500

Remaining balance which is to be paid as monthly installments

= $12495 - $1500

=$12495 − $1500

=$10995

Thus, the monthly installments are $10995.

Now, to determine the number of months needed to pay off the remaining balance. The monthly installment is need to be known.

As a result, information on monthly installments is lacking.

To know more about the installments, here

brainly.com/question/16032019

#SPJ4

The complete question is-

What necessary piece of information is missing that prevents solving the problem? By paying $1500 cash and the balance in equal monthly payments, how many months would it take to pay for a car costing$12,495?

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A sample size of n = 64 is drawn from a population whose standard deviation is o = 5.6.
AlekseyPX

Answer:

The margin of error for a 99% confidence interval for the population mean is 1.8025.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem:

\sigma = 5.6

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The margin of error for a 99% confidence interval for the population mean is 1.8025.

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