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victus00 [196]
3 years ago
7

PLEASE HELP!!! You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can yo

u do this?
Mathematics
1 answer:
ipn [44]3 years ago
6 0

Answer:

1140 ways.

Step-by-step explanation:

The applicable formula is: (n +r - 1)C(r-1), where n is the number of identical items (the candies), and r is the possible number of recipients (the kids).

The 17 identical candies, can be distributed among the 4 children in :  

=(17 + 4 - 1)C(4–1) = 20C3 ways.

= 20!/((20–3)!*3!) ways.

= 20*19*18*17!/(17!*(3*2*1)) = 20*19*18/6 ways

= 20*19*3 ways.  

=1140 ways.

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What is the 23rd term of the arithmetic sequence where a1 = 8 and a9 = 48?
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Answer:

23rd term of the arithmetic sequence is 118.

Step-by-step explanation:

In this question we have been given first term a1 = 8 and 9th term a9 = 48

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Since in an arithmetic sequence

T_{n}=a+(n-1)d

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since 9th term a9 = 48

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3 years ago
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<em>~234483279c20~</em>

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