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victus00 [196]
3 years ago
7

PLEASE HELP!!! You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can yo

u do this?
Mathematics
1 answer:
ipn [44]3 years ago
6 0

Answer:

1140 ways.

Step-by-step explanation:

The applicable formula is: (n +r - 1)C(r-1), where n is the number of identical items (the candies), and r is the possible number of recipients (the kids).

The 17 identical candies, can be distributed among the 4 children in :  

=(17 + 4 - 1)C(4–1) = 20C3 ways.

= 20!/((20–3)!*3!) ways.

= 20*19*18*17!/(17!*(3*2*1)) = 20*19*18/6 ways

= 20*19*3 ways.  

=1140 ways.

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Answer:

720 apples

Step-by-step explanation:

Let A be the number of apples in the small pack.

QTY for Small Cartons is 15A,

QTY for Big Cartons is 20(A+15) = 20A+300

From small cartons makes 25% or 1/4 of total, means the big carton makes 75% of total, or 3/4 of total. This also means the qty in big carton is 3 times of small carton

20A+300 = 3X (15A)= 45A

300 = 25A

A=12

Altogether = 15A+(20A+300) = 720 Apples

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Solve -3x^2-4x-4=0. Use the quadratic formula.
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\frac{2}{9}  =  \frac{4}{x + 8}  \\

\frac{4}{x + 8}  =  \frac{2}{9}  \\

Inverse both sides

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Multiply sides by 4

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x + 8 = 18

Subtract sides 8

x + 8 - 8 = 18 - 8

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Done...

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