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2 years ago

Which of the following IS a positive effect of the use of personal communication devices?

Computers and Technology

1 answer:

Goshia [24]2 years ago

5 0

a) Personal communication devices are used in healthcare for sending e-mails or messages to healthcare members.

b) They use these devices for calculations.

c)They can access work related medical information by using mobiles.

2) Personal communication devices use at work has positive effect on their work including reducing stress, benefiting patients care improving coordination of patient care among the healthcare team or increases unit team work.

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Please answer quick :(

Karo-lina-s [1.5K]

Answer:

1<2 or 15<6 is true

2<4 and 7< 3 is false

not(7>2) is false

6 0

1 year ago

Read 2 more answers

Which line in the following program contains the header for the showDub function? 1 #include 2 using namespace std; 3 4 void sho

Flura [38]

Answer:

The answer to this question is "15 line".

Explanation:

A function is a block of ordered, portable code used to perform a single, connected operation. The syntax of function declaration can be given as:

Syntax :

returntype functionName(parameter1, parameter2); //function prototype

or declaration

returntype functionName(parameter1, parameter2) //function definition or header of the function

{

//function body.

//function implementation

//return value;

}

In the given question the header of the showDub function is on line 15.

That's why the answer to this question is "15 line".

8 0

3 years ago

A developer designed a process in UiPath Studio that is best-suited for a simple and linear process. Which Studio workflow type

Gala2k [10]

Question options:

State Machine

Flowchart

Sequence

Global Exception Handler

Answer:

Sequence

Explanation:

Uipath is an RPA(Robotic process automation) software that is used by IT professionals and business executives in automating routine or iterative tasks in an organization. Uipath process projects incorporate different workflow types which include :sequence, flowchart, state machine and global exception handler. The sequence workflow type is used for simple linear projects that are not very complex and occupies a single activity block.

3 0

3 years ago

When a machine is having issues, an IT Support Specialist has to file an RMA, or Return Merchandise Authorization form, with the

melamori03 [73]

Answer:

The answer is "Option b"

Explanation:

This method is also known as the model is continuously developed, evaluated, applied and enhanced. It enables firms to manage transactions with its all-out returns, they can be used to calculate the final 7 digits of the Online charge level, and the wrong option can be described as follows:

In option a, It first find then arranging all the data.
In option c, It provides essential updates and saves into the file.
In option d, It is an ideal plan for a lifetime operation.

5 0

3 years ago

Read 2 more answers

Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:

horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0

3 years ago