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gulaghasi [49]
2 years ago
5

How do you model a situation in which a function behaves differently over different parts of its domain?

Mathematics
1 answer:
Eduardwww [97]2 years ago
5 0

The situation in which a function behaves differently over different parts of its domain is modeled by considering it to be a piecewise function.

Such a situation can be explained through an example:

f(x)=   { 2x, for x > 0

         {     1, for x = 0

         { -2x, for x < 0

now, when we take x value less than 0, say x= -1

    thus, f(x)= f(-1)= -2(-1) = 2 , here we used f(x) given x<0

now, when we take x value more than 0, say x= 2

    thus, f(x)= f(1)= 2(1) = 2, here we used f(x) given x>0

now, when we take x =  0,

    thus, f(x)= f(0)= 1, here we used f(x) given x=0

this is how we model picewise function, we  use f(x) as per the value of x. Following image shows plotted answer for this example.

Since inequalities given are exclusive of 0, we leave the dot at the origin unfilled. Now, for x = 0. Since the value is constant at f(x) =1, we plotted a point at (0,1)

more questions on picewise functions brainly.com/question/12089993

#SPJ4

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A person invests 9000 dollars in a bank. The bank pays 4.25% interest compounded daily. To the nearest tenth of a year, how long
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The person must invest the money in the bank for 18 years to reach $19600, if a person invests 9000 dollars in a bank and the bank pays 4.25% interest compounded daily.

Step-by-step explanation:

The given is,

                       A person invests 9000 dollars in a bank      

                      The bank pays 4.25% interest compounded daily

                      Future amount $19600

Step:1

                     Formula to calculate the future investment with compounded daily,

                                                  A = P (1+\frac{r}{n})^{nt}................................(1)

                   Where, A - Future amount

                                P - Initial investment

                                r - Interested rate

                                n - No.of times for a year

                                t - No.of years

Step:2

              From the given values,

                      A = $ 19600

                      P = $ 9000

                       r = 4.25 %

                      n = 365  ( ∵ Compounded daily )

           Equation (1) becomes,

                                        19600 = 9000(1+\frac{0.0425}{365})^{365t}

                                         \frac{19600}{9000}= (1+0.000116438)^{365t}

                                   2.177778=(1.000116438)^{365t}

            ( Take log on both sides )

                               log 2.17778= log (1.000116438)^{365t}

                               log 2.17778=( 365t)log (1.000116438)

           Substitute the log values,

                                  0.338014 = (365t)(0.000050565)

                                \frac{0.338014}{0.000050565}= 365t

                                6684.6842 = 365t

                                              t = \frac{6684.6842}{365}

                                                 = 18.314

                                                 ≅ 18 years

                          No.of years, t = 18 years

Result:

              The person must invest the money in the bank for 18 years to reach $19600, if a person invests 9000 dollars in a bank and the bank pays 4.25% interest compounded daily.

3 0
3 years ago
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