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4 years ago

Sophie is eating a 50-gram chocolate bar which contains 30% of coca. How many grams of coca are in the chocolate bar?

2 answers:

7 0

So 30% of the chocolate bar is cocoa and if the bar is 50g it's the following:

(50x30)/100 = 15

which means 15 grams of the chocolate bar is pure cocoa

Alekssandra [29.7K]4 years ago

3 0

30/100 * 50 = 15 gram of coco

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Kazeer [188]

Answer:

$x^{2} - 5x - 24$

Step-by-step explanation:

( x + 3 )( x - 8 ) =

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Find the value of each variable in the parallelogram

wlad13 [49]

Answer:

B= 90

C= 80

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Step-by-step explanation:

So let’s start with the bottom angles.

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Now for d.

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3 years ago

2x - y = 6<br>4<br>x-y<br>13<br>anch

yanalaym [24]

Answer:

x=-7, y= -20

Step-by-step explanation:

2x - y =6

x - y = 13

when I subract (x-y =13 ) from (2x-y =6)

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3 years ago

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Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

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