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2 years ago

If a jeep averages 30.5 miles per gallon, how many miles will it travel on 14 gallons of gas?

Mathematics

1 answer:

Aleks04 [339]2 years ago

7 0

Answer: 427 miles

Step-by-step explanation:

if the jeep averages 30.5 miles per gallon, and you have 14 gallons, then you will need to multiply 30.5*14 to get your answer, which is 427

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Aunt Barb's Salad Dressing requires 1/3 cup olive oil and 1/6 cup balsamic vinegar. How much dressing does this recipe make?

anyanavicka [17]

Answer:

1/2 cup of dressing

Step-by-step explanation:

To find the total amount of dressing, we just need to add up the amounts of olive oil and balsamic vinegar.

1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2 cup

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3 years ago

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What is the area of a square with a side length of 7 units

Alexandra [31]

Answer:

343

Step-by-step explanation:

L×W×H= area

squares have equal L W And H

7×7×7= 343

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3 years ago

romeo ordered a bouquet of roses for his girlfriend. each rose cost $2.95. and the delivery charge was $8.50. if the total cost

LenaWriter [7]

Okay first you should subtract 8.50 from 61.60 because the delivery charge doesn't count. 61.60-8.50=53.1. now divide 53.1 by 2.95. 53.1÷2.95=18. Romeo ordered 18 roses for his girlfriend.

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3 years ago

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during a sale a dress is marked down for a selling price of $90 to a sale price of $81 what is the percent markdown

zavuch27 [327]

Answer:

10%

Step-by-step explanation:

divide 90 into 81

so 81/90=.9

multiply that by 100 and you get 90 so 81 is 90% of 90 so it got marked down 10%

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4 years ago

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II. Let f(x) = 9 – x , g(x) = x2 + x, and h(x) = x – 2. Compute the following:

Neko [114]

Answer:

$h(g(x))=x^2+x-2$

$h(g(f(x))= x^2-19x+88$

Step-by-step explanation:

<u>Composite Function</u>

Suppose f(x) and g(x) are real functions, the composite function named $(f\circ g)(x)$ is defined as:

$(f\circ g)(x)=f(g(x))$

The composite function can be found by substituting g into f.

We are given these functions:

$f(x)=9-x$

$g(x)=x^2+x$

$h(x)=x-2$

Find:

a) h(g(x))

Substituting g into h:

$h(g(x))=x^2+x-2$

b) h(g(f(x))

First we find g(f(x)):

$g(f(x))=(9-x)^2+(9-x)$

Operating:

$g(f(x))=81-18x+x^2+9-x$

Simplifying:

$g(f(x))=90-19x+x^2$

Now find h(g(f(x)) replacing the above equation into h:

$h(g(f(x))= 90-19x+x^2-2$

Simplifying and rearranging:

$h(g(f(x))= 88-19x+x^2$

$h(g(f(x))= x^2-19x+88$

3 0

3 years ago