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prohojiy [21]
1 year ago
10

Find the Perimeter of the figure below, composed of a parallelogram and one

Mathematics
1 answer:
Neporo4naja [7]1 year ago
7 0

The perimeter of the figure to the nearest tenth is 44.6 units

<h3>Perimeter of a figure?</h3>

The perimeter of a figure is the sum of the whole sides.

Therefore,

A parallelogram has opposite sides equal to each other.

Therefore, the perimeter of the figure is as follows;

The figure combines a parallelogram and a semi circle.

Therefore,

perimeter of the figure = 4 + 14 + 14 + πr

perimeter of the figure = 32 + 3.14 × 4

perimeter of the figure = 32 + 12.56

perimeter of the figure = 44.56

perimeter of the figure ≈ 44.6 units

learn more on perimeter here: brainly.com/question/22532312

#SPJ1

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Which expression represents each mathematical phrase?
olganol [36]

Answer:

Step-by-step explanation:

add 12 and a number: 12 + c

subtract a number from 12: 12 - c

divide a number by 12: c : 12 or c/12

multiply 12 by a number: 12 · c = 12c

5 0
2 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
Zapisz w jak najprostszej postaci:<br> a) -x-4(1-x)<br> b) 3(5x-2)-5(3-4x)<br> c) √2(3-x)-2(1-x√2)
Sonja [21]

Answer:

Step-by-step explanation:

a) -x-4(1-x)  =

− 2 x −4 ( 1 − x ) .

2 x − 4

b) 3(5x-2)-5(3-4x)  =

3 ⋅ (5 x − 2 ) − 5 ⋅ ( 5 − 4 x )

35 x  −  31

c) √2(3-x)-2(1-x√2) =

√ 2 x ⋅ ( 3 −x ) − 2 ⋅( 1 − x √ 2 ) .

2 x √ 2 + 3 √ 2 x -√ 2 x x − 2

4 0
3 years ago
When do u use two number lines to compare two fractions
jeka94

Answer:

You need two number lines to compare two fractions when their denominators are different. The procedure is that you draw to segment lines of the same length but divede each line according to its denominator and then compare the place of the points that mark the fraction numbers, the line that content the marke further away from the start end will be indicate the greater fraction. For example, the fractions 3/4 and 7/10. One line will be divided inot 4 equidistant segments, and the other with 10 equidistant segments. The fraction 3/4 will be represented with 3 marks on the first line, and the fraction 7/10 will be represented with 7 marks on the second line. Now you can compare the size of the two segments marked adn decide which fraction is greater.

GOOD LUCK!

credits to the internet/brainly whom gave me these answers. ; )

5 0
3 years ago
Solve the proportion: 20/16 = x/80 question 19 options: 6.25 1600 100 160
Aloiza [94]
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8 0
3 years ago
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