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kiruha [24]
3 years ago
5

Kiara baked 30 oatmeal cookies and 48 chocolate chip cookies to package in plastic containers for her teacher

Mathematics
2 answers:
Crazy boy [7]3 years ago
4 0

Number of oatmeal cookies with Kiara = 30

Number of chocolate chips cookies with Kiara = 48

To find the greatest number of container neded so that there are equal amount of each cookies in each , we have to find the HCF of 30 and 48 .

Factors of 32 = 1 , 2 , 4 , 6 , 8 , 16 and 32

Factors of 48 = 1 , 2 , 3 , 4 , 6 , 8 , 12 , 16 , 24 and 48

Common and highest among these factors = 16

Which means 16 is the HCF of 32 and 48 .

∴ Kiara will need 16 plastic containers .

Black_prince [1.1K]3 years ago
3 0

Answer: 16 containers?

Step-by-step explanation:

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Effect of the raise on the following characteristics of the data

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The outline shape of the distribution will the same but higher by $1,000

(b) The mean of the data is given as follows;

\overline x = \dfrac{\sum (f_i \cdot x_i)}{\sum f_i}

Therefore, following an increase of $1,000, we have;

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Median;

Given that all salaries, x_i, are increased by $1,000, the median salary, x_{med}, is also increased by $1,000

Therefore;

  • The correct response is that the median is increased by $1,000

(c) The standard deviation, σ, is given by \sigma =\sqrt{\dfrac{\sum \left (x_i-\overline x  \right )^{2} }{n}};

Where;

n = The number of teaches;

Given that, we have both a salary, x_i, and the mean, \overline x, increased by $1,000, we can write;

\sigma_{new} =\sqrt{\dfrac{\sum \left ((x_i + 1000) -(\overline x  + 1000)\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x  - 1000\right )^{2} }{n}}

\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 -\overline x  - 1000\right )^{2} }{n}} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}}

\sigma_{new} = \sqrt{\dfrac{\sum \left (x_i + 1000 - 1000 - \overline x\right )^{2} }{n}} =\sqrt{\dfrac{\sum \left (x_i-\overline x  \right )^{2} }{n}} = \sigma

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\sigma_{new} = \sigma; <u>The standard deviation stays the same</u>

Interquartile range;

The interquartile range, IQR = Q₃ - Q₁

New interquartile range, IQR_{new} = (Q₃ + 1000) - (Q₁ + 1000) = Q₃ - Q₁ = IQR

Therefore;

  • <u>The interquartile range stays the same</u>

Learn more here:

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