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frosja888 [35]
1 year ago
5

Nisha collects comic books, and she convinced her friend Hakim to start collecting as well. Every week, they go to the store tog

ether, and they each buy a new comic book. This table shows how many books they each have:

Mathematics
1 answer:
andreyandreev [35.5K]1 year ago
6 0

By using the given table, we will get the linear equation:

h = n - 9

<h3>How to find the equation for Hakim?</h3>

We know that they always get comic books together, so always that Nisha's collection increases by one, Hakim's collection will also increase by one, so we will have a linear equation.

Now, if you look at the given table, you can see that Hakim's collection is always 9 units less than Nisha's collection, then the linear equation that models the relation between the two collections, h and n, is really straightforward, it will be:

Hakim's collection = Nisha's collection - 9

Using the variables, we get:

h = n - 9

That is the linear equation Hakim wanted.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.
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a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

p(m) = 0.52 (which corresponds to 52%)

While the probability that the birth is a female can be written as

p(f) = 0.48 (which corresponds to 48%)

Here we want to calculate the probability that over  2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male  does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

p(mm)=p(m)\cdot p(m)

And substituting, we find

p(mm)=0.52\cdot 0.52 = 0.27

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

p(ff)

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

p(ff)=p(f)\cdot p(f)

And substituting

p(f)=0.48

We find:

p(ff)=0.48\cdot 0.48=0.23

Which means 23%.

c)

In this case, we want to find the probability they have exactly one male and exactly one female child. This is given by the sum of two probabilities:

- The probability that 1st child is a male and 2nd child is a female, namely p(mf)

- The probability that 1st child is a female and 2nd child is a male, namely p(fm)

So, this probability is

p(mf Ufm)=p(mf)+p(fm)

We have:

p(mf)=p(m)\cdot p(f)=0.52\cdot 0.48=0.25

p(fm)=p(f)\cdot p(m)=0.48\cdot 0.52=0.25

Therefore, this probability is

p(mfUfm)=0.25+0.25=0.50

So, 50%.

Learn more about probabilities:

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Two golfers completed one round of golf. The first golfer had a score of +6 and the second golfer had a score of –3. How many mo
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                                             Question 16

Given that two golfers completed one round of golf.

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                                             Question 17

When we talk about credit, it means:

Credit = +

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Debit = -

Thus,

Credit = +84

Debt = -29

Balance = 84 + (-29)

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Thus, the balance is: 55

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Answer:

z=3.8196

Step-by-step explanation:

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