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1 year ago

Help please!! … help

Mathematics

1 answer:

Bad White [126]1 year ago

6 0

Answer:

True ................

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Ruby conducted a survey and found that 5/6 of her classmates have a pet and 2/3 of them are dogs what fraction of her classmates

lina2011 [118]

This is how I would solve it, I would act as if there were 36 people in the class.
36÷6=6×5=30
30÷3=10×2=20
20/36=10/18=5/9
You could also try another number such as 24;
24×(5÷6)=20
20×(2/3)=13.3(3 repeating)
13.333/24=5/9
5/9 people have dogs.
Tell me if this helps.

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3 years ago

Provide a radian measure of an angle that is 5/8 of a revolution counterclockwise from the x-axis.

tia_tia [17]

I’m pretty sure but not so sure I think it is 180

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2 years ago

URGENT PLEASE HELP ME

Salsk061 [2.6K]

Answer:

(5,11)

Step-by-step explanation:

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3 years ago

Which is the same as 10^-3<br>A. 0.0001<br>B.0.001<br>C.3<br>D.1000<br>

pishuonlain [190]

Answer:

Step-by-step explanation:

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2 years ago

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Two cruise ships leave the same port with a 35° angle between their path. Cruise A is traveling at 18 miles per hour and Cruise

GuDViN [60]

Answer:

$20\:\mathrm{miles}$

Step-by-step explanation:

After travelling two hours, the two cruise ships form a triangle. One of the legs of this triangle will be the distance Cruise A travelled, and another will be the distance Cruise B travelled. We can find the distance they travel using:

$s=\frac{d}{t}, d=s\cdot t$

Cruise A is travelling at 18 miles per hour for 2 hours. Therefore, Cruise A has travelled:

$d=s\cdot t=18\cdot 2=36\:\mathrm{miles}$

Cruise B is travelling at 15 miles per hour for 2 hours. Therefore, Cruise B has travelled:

$d=s\cdot t=15\cdot 2=30\:\mathrm{miles}$

Because we are given the angle between these legs, we can use the Law of Cosines to find the third leg. The Law of Cosines is given by:

$c^2=a^2+b^2-2ab\cos C$ , where $a$ , $b$ , and $c$ are interchangeable. Let $c$ represent the distance between the two cruises. We have:

$c^2=36^2+30^2-2\cdot36\cdot30\cdot \cos 35^{\circ},\\c^2=426.63,\\c\approx \fbox{$20\:\mathrm{miles}$}$ (one significant figure).

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2 years ago

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