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4 years ago

Evaluate. 2n - 1, where n = 7

Mathematics

2 answers:

tino4ka555 [31]4 years ago

8 0

Expression: 2n - 1

When n = 7
2n - 1 = 2(7) = 1 = 14 - 1 = 13

erica [24]4 years ago

3 0

2(7)-1=14-1=13. Plug in n=7.

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Find the indicated limit, if it exists.

jok3333 [9.3K]

For the limit to exist, the limits from either side must also exist and be identical. We have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}(x+3)=2+3=5$

$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(3-x)=3-2=1$

Since the limits do not match, the overall limit does not exist.

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3 years ago

What expression is equivalent to 4/7+1 1/3

omeli [17]

Answer:

1 19/21

Step-by-step explanation:

12/21+1 +7/21

19/21+1

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3 years ago

Explain why x=-8 is not part of the domain of the function y=log2(x)

Masteriza [31]

Answer:

See Below.

Step-by-step explanation:

By the definition of the logarithm, if we have:

$y=\log_{2}x$

This means that we have some value y such that:

$\displaystyle 2^y=x$

If x is -8, then:

$2^y=-8$

As you can see, there is no real value* that can make the result negative. No matter what the value of y is, we will simply get another positive value.

So, -8 or any other negative value or zero is not included in our domain. 0 is not included because, likewise, we can’t raise 2 to a power and get 0 as a result.

*There is no real value for which 2 raised to y is -8. However, as you will learn much much later, there are in fact infinitely many complex (imaginary) solutions such that 2 raised to y is indeed -8.

3 0

3 years ago

If, in a monopoly market, the demand for a product is p = 185 − 0.10x and the revenue function is r = px, where x is the number

never [62]

Answer:

The price that'll maximize revenue is $p=92.5$

Step-by-step explanation:

We know that the revenue function is $r = px$ where x is the number of units sold and p is the demand function given by $p = 185 - 0.10x$ .

Therefore,

$r = px \\r=(185 - 0.10x)x\\r=185x-0.1x^2$

The maximums of a function are detected when the derivative is equal to zero so, to find what value of x maximizes the revenue function, we must find the derivative of the revenue function ( $\frac{dr}{dx}$ ) and set it equal to 0.

$\frac{d}{dx} r=\frac{d}{dx} (185x-0.1x^2)\\\\\frac{d}{dx} r=\frac{d}{dx}\left(185x\right)-\frac{d}{dx}\left(0.1x^2\right)\\\\\frac{d}{dx} r=185-0.2x$

$185-0.2x=0\\185\cdot \:10-0.2x\cdot \:10=0\cdot \:10\\1850-2x=0\\1850-2x-1850=0-1850\\-2x=-1850\\\frac{-2x}{-2}=\frac{-1850}{-2}\\x=925$

Therefore, the price that'll maximize revenue is

$p = 185 - 0.10(925)\\p=92.5$

3 0

3 years ago

Could you please help me I can't figure it out

Charra [1.4K]

It’s not clear enough

8 0

3 years ago