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Natalka [10]
3 years ago
12

Evaluate. 2n - 1, where n = 7

Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0
Expression: 2n - 1

When n = 7
2n - 1 = 2(7) = 1 = 14 - 1 = 13
erica [24]3 years ago
3 0
2(7)-1=14-1=13. Plug in n=7.
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The answer is ten inches 
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If 7=42,6=30,5=20 then 3=? find it's value​
AleksandrR [38]

Answer:

6

Step-by-step explanation:

7=42 is 7*6

6=30 is 6*5

5=20 is 5*4; it's multiplied by the number below it, so 3 will be 3*2

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Three sisters each purchase two dresses and a purse the purse costs 26.00 if the grand total was 205.50 how much did each dress
Oliga [24]
3 sisters bought 2 x 3 = 6 dress and and 1 x 3 = 3 purses.
3 sisters bought 6 dresses and and 3 purses.

Find 3 purses:
1 purse = $26
3 purses = $26 x 3 = $78

Find 6 dresses:
Total = $205.50 
6 dresses = $205.5 - $78
6 dresses = $127.50

Find 1 dress:
6 dresses = $127.50
6 dresses = $127.50 ÷ 6 
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Answer: $21.25



6 0
3 years ago
A company produces and sells homemade candles and accessories. Their customers commonly order a large candle and a matching cand
Butoxors [25]

Answer:

P(T<683) = 0.1587 = 15.87% ≈ 16%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Sum of normal variables:

When two normal variables are added, the mean is the sum of the means, while the standard deviation is the square root of the sum of the variances.

The weights of these candles have a mean of 500g and a standard deviation of 15g. The weights of the candle stands have a mean of 200g and a standard deviation of 8g.

The package consists of one candle of each type. So

\mu = 500 + 200 = 700

\sigma = \sqrt{15^2 + 8^2} = 17

Find the probability that the total weight is under 683g.

This is the pvalue of Z when X = 683.

Z = \frac{X - \mu}{\sigma}

Z = \frac{683 - 700}{17}

Z = -1

Z = -1 has a pvalue of 0.1587

So

P(T<683) = 0.1587 = 15.87% ≈ 16%.

6 0
3 years ago
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The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op
andreev551 [17]

<u>B) </u>x   =4.28

<u>C) </u> volume =  135.25cm^3 .

<u>Step-by-step explanation:</u>

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = length(width)

⇒ Area = length(width)

Putting values according to question we get :

⇒ 58 = (2x+5)(x)

⇒ 58 = (2x^2+5x)

⇒  2x^2+5x - 58 = 0

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒  2x^2+5x - 58 = 0

By quadratic formula

⇒ x   = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x   = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}

⇒ x   = \frac{-5 \pm 22.11}{4}

⇒ x   = \frac{-5 + 22.11}{4} , x   = \frac{-5 - 22.11}{4}    { Since side can't be negative ! }

⇒ x   =4.28

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28

We know that volume is given by :

⇒ length(width)(height)

⇒ 13.86(4.28)(2.28)

⇒ 135.25cm^3

Therefore , volume =  135.25cm^3 .

7 0
3 years ago
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