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anastassius [24]
1 year ago
10

Determine the solutions of the equation: the absolute value quantity two thirds times x plus 2 end quantity minus 8 equals 0 x =

−9 and x = 9 x = −15 and x = 4 x = −15 and x = 9 x = −15 and x = 15
Mathematics
1 answer:
damaskus [11]1 year ago
4 0

The solution to the given absolute value equation are x = 9 and-15

<h3>Solving absolute value expression</h3>

Given the absolute expression below;

|2/3x+2| -8 = 0

Solve the expression for the value of x

Given

|2/3x+2| -8 = 0

Add 8 to both sides

|2/3x+2| = 8

2/3x = 8 - 2

2/3x = 6

2x = 18

x = 9

If the modulus expression negative;

-(2/3x+2) -8 = 0

-2/3x - 2 = 8

-2/3x = 10

-2x = 30

x = -15

Hence the solution to the given absolute value equation are x = 9 and-15

Learn more on absolute value equation here: brainly.com/question/1542900

#SPJ1

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Kitty [74]

For this case we have the following apple picking options, in dozens:

<em>Tyler:</em>

\frac {3} {3} = 1

Tyler picked up a dozen.

<em>Olivia:</em>

\frac {5} {6} = 0.833

Olivia collected 0.833 dozen apples.

<em>Samantha:</em>

\frac {2} {3} = 0.667

Samantha collected 0.667 dozens of apples.

Thus, it is observed that Samantha collected the least amount of apples.

ANswer:

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6 0
3 years ago
A book sold 35,100 copies in its first month of release. Suppose this represents 9.2% of the number of copies sold to date. How
inessss [21]

Answer:

Total number of copies sold till date are 381522.

Step-by-step explanation:

It is given in the question the book sold 35100 copies in its first month of release and this number is 9.2% of the number of copies sold till date.

To find is how many copies have been sold.

Let the total number of copies sold be = A

Therefore 9.2% × A = 35100

\frac{9.2}{100}A=35100

A=\frac{35100\times 100}{9.2}

A = 381521.74 ≅381522 copies

3 0
3 years ago
Maddie tried to divide 160 stickers equally amongst herself and 5 friends. There was some stickers left over, so she kept them.
Nutka1998 [239]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
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