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Mathematics

1 answer:

maks197457 [2]3 years ago

6 0

Answer:

Step-by-step explanation:

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Use the arc length formula and the given information to find r. s = 12 cm, 0 = 360; r = ?

hjlf

use s=r0

but first convert 360 degree to radian
you will get 6.284 radian

then you substitute and get the answer!

12= r (6.284)
r= 1.91 cm

8 0

3 years ago

Brett painted three walls. Each wall was 9 ft tall and 12 ft long. How much wall area did he paint

julsineya [31]

Answer:

First we need to calculate the are of each wall, since we alredy knew the length (l) and the width (w) which is the height of the wall in this case:

A = wl = 9 . 12 = 108 (ft²)

We also know that he painted 3 walls, we need to multiply our first result by 3, in other words, the area of wall that Brett painted is the sum of the area of three walls: 108 . 3 = 324 (ft²)

8 0

4 years ago

Read 2 more answers

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$