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2 years ago

Find the equation of this line. A y = [?] + [ 1 Enter D

Mathematics

1 answer:

VMariaS [17]2 years ago

8 0

The equation of this line is given by:

y = -1/2x + 1.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

Given two points, the slope is given by <u>change in y divided by change in x</u>. In this problem, we have points (0,1) and (2,0), hence:

m = (1 - 0)/(0 - 2) = -1/2.

Point (0,1) also means that the y-intercept is of b = 1, hence the equation of this line is given by:

y = -1/2x + 1.

More can be learned about linear functions at brainly.com/question/24808124

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The weights of 83 randomly selected windshields were found to have a variance of 1.88. Construct the 95% confidence interval for

Morgarella [4.7K]

Answer:

95% confidence interval for the population variance = (1.42 , 2.62).

Step-by-step explanation:

We are given that the weights of 83 randomly selected windshields were found to have a variance of 1.88.

<em>So, firstly the pivotal quantity for 95% confidence interval for the population variance is given by;</em>

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, $s^{2}$ = sample variance = 1.88

$\sigma^{2}$ = population variance

n = sample of windshields = 83

So, 95% confidence interval for population variance, $\sigma^{2}$ is;

P(58.85 < $\chi^{2} __8_2$ < 108.9) = 0.95 {As the table of $\chi^{2}$ at 82 degree of freedom

gives critical values of 58.85 & 108.9}

P(58.85 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 108.9) = 0.95

P( $\frac{ 58.85}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{108.9}{(n-1)s^{2} }$ ) = 0.95

P( $\frac{ (n-1)s^{2}}{108.9 }$ < $\sigma^{2}$ < $\frac{ (n-1)s^{2}}{58.85 }$ ) = 0.95

<em><u>95% confidence interval for</u></em> $\sigma^{2}$ = ( $\frac{ (n-1)s^{2}}{108.9 }$ , $\frac{ (n-1)s^{2}}{58.85 }$ )

= ( $\frac{ (83-1)\times 1.88}{108.9 }$ , $\frac{ (83-1)\times 1.88}{58.85 }$ )

= (1.42 , 2.62)

Therefore, 95% confidence interval for the population variance of the weights of all windshields in this factory is (1.42 , 2.62).

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3 years ago

Before a new variety of frozen muffins is put on the market, it is subjected to extensive taste testing.People are asked to tast

Greeley [361]

Answer:

An experimental study

Step-by-step explanation:

An experiment deliberately imposes some treatment on individuals in order to observe their responses.

An experimental studies formulates some conditions in order to make an inference. An observational study tries to gather information without disturbing the scene they are observing.

This is then an experiment because people are deliberately asked to taste two muffins and asked for their response.

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3 years ago

23% of $640<br> Please show work

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23/100×$640=147.2 is the answer

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professor190 [17]

Answer:

Step-by-step explanation:

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Find the equation of this line. A y = [?] + [ 1 Enter D​

Find the equation of this line. A y = [?] + [ 1 Enter D