Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Answer:
b. typically contain more circuits in the network than in star or ring networks
Explanation:
In mesh architecture, all computers are connected to each other. In mesh all nodes connect directly and non hierarchical to each other so as to efficiently route data.
Mesh combines the benefits of both ring and star networks. It usually provide relatively short routes through the network (compared to ring networks) and provide many possible routes through the network to prevent one circuit from becoming overloaded (as compared to star network). Mesh network uses decentralized routing with each network performing its own routing.
Mesh network typically contain more circuits in the network than in star or ring networks and are more expensive than ring networks
Answer:
true
Explanation:
because it needs a interpreter so that it could be more developed