Answer:
(0.63789 ; 1.38211 )
Given that:
Mean, xbar = 1.01
Standard deviation, s = 0.29
Sample size, n = 7
Confidence interval : xbar ± margin of error
Margin of Error = Tcritical * s/sqrt(n)
Degree of freedom (df) = n - 1 = 7 - 1 = 6
Hence Tcritical = 3.143
Margin of Error = 3.143 * 0.29/sqrt(6)
Margin of error = 0.37211
Lower boundary = (1.01 - 0.37211) = 0.63789
Upper boundary = (1.01 + 0.37211) = 1.38211
(0.63789 ; 1.38211 )
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