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Jobisdone [24]
3 years ago
14

Domain Range Discrete or continuous?

Mathematics
1 answer:
storchak [24]3 years ago
3 0

Answer:continuous

Step-by-step explanation:

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Help!!!!!!!!!!!!!!! Simplify 4^(-2)
user100 [1]

hello there! Your answer would be 0.0625 or 1/16.

In this question, you are being asked to multiply 4 to the -2nd power. Your answer would be whatever the inverse of 4 to the 2nd power. Well, 4 to the 2nd power is equivalent to 16, or 16/1, so just slip the numerator and denominator values and you get 1/16. (In decimal form it is 0.0625)

I hope this helps and have a great day!

8 0
3 years ago
What is the mean of the following data values?<br> 53, 71, 89, 10, 62
Crazy boy [7]

Answer:

Ok so I kind of want you to learn how to do this because its really easy. You add up all of the numbers then you count how many numbers there are and you divide of all of the numbers that you added up  and the sum of how many numbers there are for example if I had 34,65, 75, 85, 14, and 23 It would be 34+65+75+85+14+23= 269. There are 6 numbers so 269 divided by 6 and you get 44.8 IF THIS HELPS!!

Step-by-step explanation:

6 0
4 years ago
A scatter plot containing the point (5,9) has the regression equation y = -x-3 (see photo)
Tatiana [17]
The residual is the difference between the plotted point and the line of best fit.

We first need to know the point at x=5 for the line of best fit.
y1 = -(5) - 3 = -8

Now we need to find the difference between the line of best fit and the plotted point.
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7 0
4 years ago
PLEASE HELP!! what is the horizontal asymptote of f(x)=2/3^x? Is it on the x-axis or the y-axis?
anygoal [31]

Hey there! :)

Answer:

y = 0, also known as the x-axis.

Step-by-step explanation:

The equation f(x) = \frac{2}{3} ^{x} is an exponential function.

There is an asymptote at y = 0, or the x-axis because:

\frac{2}{3} ^{x}\neq  0

An exponential function, unless containing a vertical shift, can never cross the x-axis resulting in an asymptote at y = 0.

4 0
4 years ago
The first two steps in determining the solution set of the system of equations, y = x2 – 2x – 3 and y = –x 3, algebraically are
rodikova [14]
Is that supposed to be : y = -x^3 ?? 
<span>i have the same question </span>
<span>yes it is </span>
<span>so when you write x2 you mean x^2 and 2x is 2^x also ? </span>
<span>is it an exponent
sorry, need ponts
</span>
5 0
3 years ago
Read 2 more answers
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