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Shkiper50 [21]
2 years ago
15

If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If, instead, you throw it downwar

d, its downward acceleration after release is?
Physics
1 answer:
Korvikt [17]2 years ago
4 0

If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If instead, you throw it downward, its downward acceleration after release is 9.8 m/s2.

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration. Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.

A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific designation is given to the numerical value for an object in free fall because it is such an essential value. The longer an object is in free fall, the faster it descends toward the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.

To know more about acceleration refer to: brainly.com/question/14468548

#SPJ4

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denis23 [38]

Answer:

On the magnitude of the charges, on their separation and on the sign of the charges

Explanation:

The magnitude of the electric force between two charges is given by

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

From the formula, we see that the magnitude of the force depends on the following factors:

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Moreover, the direction of the force depends on the sign of the two charges. In fact:

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3 years ago
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Juliette [100K]

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An object that is moving must have a change in A) its speed. B) its position. C) its acceleration. D) its applied force.
denis-greek [22]

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salantis [7]

Answer:

568.18 N

Explanation:

From the question,

The formula for gravitational potential is given as

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Where Ep = Gravitational potential, m = mass of the diver,h = Height.

But,

W = mg.................... Equation 2

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Substitute equation 2 into equation 1

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Make W the subject of the equation

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Given: Ep = 25000 J, h = 44 m

Substitute into equation 3

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ra1l [238]

Answer:

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