What is an important physical property that is used to identify, sort, and describe.

A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma

tresset_1 [31]

Answer:

Explanation:

a. Given that:

$m-$ mass of first & second piece, $3m-$ mass of 3rd piece, $\bar v_1$ -velocity of first piece( $-23\dot i \ m/s$ ) and $\bar v_2$ as velocity of 2nd piece ( $-23\dot j \ m/s$ )

Let $\bar v_3$ be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

$m\bar v_1 +m\bar v_2 +3m \bar v_3=0$ #Dividing both sides by $m, m\neq 0$

$\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)$

#Plug the $\bar v_1 ,\bar v_2$ values:

$\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)$

#So the magnitude of the third piece is:

$|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s$

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the $x$ -axis), we find $\angle \theta$ . The angle is obtained by getting the tan inverse as:

$\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree$

-The direction of the magnitude (angle relative to the x-axis) is 45°

6 0

3 years ago

We are able to walk forward because _____.

Diano4ka-milaya [45]

Cuz Of Newton’s third law, every actions there is an equal and opposite reaction.

7 0

3 years ago

Read 2 more answers

A small block of mass m = 0.032 kg can slide along the frictionless loop-the-loop, with loop radius R = 12 cm. The block is rele

Lunna [17]

Answer:

Part a)

$W = 0.15 J$

Part b)

$W = 0.11 J$

Part c)

$U = 0.19 J$

Part d)

$U = 0.038 J$

Part e)

$U = 0.075 J$

Part f)

It is independent of the speed of the object so all part answers will remain the same

Explanation:

Part a)

As we know that Point P is at height 5R while point Q is at height R

so the work done by gravity from P to Q is given as

$W = mg(5R - R)$

$W = 0.032(9.8)(4)(0.12)$

$W = 0.15 J$

Part b)

When it reaches to the top of the loop then its final height from ground is

h = 2R

so work done from P to Q is given as

$W = mg(5R - 2R)$

$W = 3mgR$

$W = 0.11 J$

Part c)

Potential energy at P point is given as

$U = mgH$

$U = 0.032(9.8)(5)(0.12)$

$U = 0.19 J$

Part d)

Potential energy at Q point is given as

$U = mgH$

$U = 0.032(9.8)(0.12)$

$U = 0.038 J$

Part e)

Potential energy at top point is given as

$U = mgH$

$U = 0.032(9.8)(2)(0.12)$

$U = 0.075 J$

Part f)

Since all the answer from part a) to part e) depends only upon the position of the object.

So here we can say that it is independent of the speed of the object so all part answers will remain the same

8 0

4 years ago

A 1.00 kg, 2.00 kg and 5.00 kg object are released from the same height at the

Lady bird [3.3K]

Answer:

George

Explanation:

George is correct because no matter the mass all objects will hit the ground at once because each has a certain amount of gravity needing them to pull it down for example your weight the bigger the person the heavier.

7 0

3 years ago

The two uniform, slender rods B1and B2, each of mass 2kg, are pinned together at P, and then B1is suspended from a pin at O. (Th

Bezzdna [24]

Answer:

hello the diagram relating to this question is attached below

a) angular accelerations : B1 = 180 rad/sec, B2 = 1080 rad/sec

b) Force exerted on B2 at P = 39.2 N

Explanation:

Given data:

Co = 150 N-m ,

a) Determine the angular accelerations of B1 and B2 when couple is applied

at point P ; Co = I* ∝B2'

150 = ( (2*0.5^2) / 3 ) * ∝B2

∴ ∝B2' = 900 rad/sec

hence angular acceleration of B2 = ∝B2' + ∝B1 = 900 + 180 = 1080 rad/sec

at point 0 ; Co = Inet * ∝B1

150 = [ (2*0.5^2) / 3 + (2*0.5^2) / 3 + (2*0.5^2) ] * ∝B1

∴ ∝B1 = 180 rad/sec

hence angular acceleration of B1 = 180 rad/sec

b) Determine the force exerted on B2 at P

T2 = mB1g + T1 -------- ( 1 )

where ; T1 = mB2g ( at point p )

= 2 * 9.81 = 19.6 N

back to equation 1

T2 = (2 * 9.8 ) + 19.6 = 39.2 N

3 0

3 years ago