Total balance in Mr. Copley at the end of the month = $1473.61.
Initial deposite = $75 (not shown in his checkbook).
Let us assume his balance at the beginning of the month = x.
Total balance at the end of the month = The balance at the beginning of the month + total deposite.
$1473.61 = x + 75.
Subtracting 75 from both sides, we get
1473.61 -75 = x + 75 -75.
1398.61 = x.
Therefore, his balance at the beginning of the month was $1398.61.
Answer:
9x³ + 27x²
Step-by-step explanation:
What the question is asking is to multiply f(x) and g(x) together:
Step 1: Write out expression
(fg)(x) = 3x²(3x + 9)
Step 2: Distribute
(fg)(x) = 9x³ + 27x²
Y= (x-2)² + 5. We can write it as : y-5 = (x-2)². The general equation of a quadratic function is :
(y-k) = a(x-h)², where h and k are the vertex of the parabola and a, the coefficient which determines whether the parabola opens upward or downward.
So, y-5 = (x-2)²
Having said that we can say that the VERTEX( 2,5) and since a=1 (a>0) the parabola is open upward OR it passes by a MINIMUM (Then the vertex is minimum)
The domain (x- value) is all Real { x|x = -∞ to x=+∞}
The Range (y-value) is all y ≥ 5
Hope this helps you :D
Answer is (D) 3^11
Step by step:
3^10+3^10+3^10
Collect like terms
=3x3^10
Calculate
Your solution is
3^11
