Draw two different figures that each have a perimeter of 14 units .Then find the aera of each

1 answer:

7 0

You could make a rectangle with the base of 5 units and a height of 2 units. So the perimeter would be 5+5+2+2 which is 14 and the area would be base times height ,in this case it would be 5 times 2 which is 10 squared units. The 2nd figure would be an isosceles triangle with the base of 6 units the height of 2 units, and the 2 other sides would be 4 units. The perimeter would be 6+4+4 which equals to 14 units and the area, 6 times 2 and the half of that is 6 so the area for the triangle is 6 units squared

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iren2701 [21]

Answer:

The distance between points A and B is 13

Step-by-step explanation:

We need to find distance between points A and B

Looking at the graph,

Point A : (2,6) and Point B: (-3,-6)

We need to find the distance between these points.

The formula used is: $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

We have Points A : (2,6) and B: (-3,-6)

So, $x_1=2, y_1=6, x_2=-3, y_2=-6$

Putting values in formula and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\Distance=\sqrt{(-3-2)^2+(-6-6)^2} \\Distance=\sqrt{(-5)^2+(-12)^2} \\Distance=\sqrt{25+144} \\Distance =\sqrt{169}\\Distance = 13$