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1 year ago

Jacque has 3 L of a 50% antifreeze mixture. How much 75% mixture should be added to get a mixture that is 60% antifreeze?

Mathematics

1 answer:

Diano4ka-milaya [45]1 year ago

8 0

You need to add 2 L of the 75% mixture to get a mixture that is 60% antifreeze.

<h3>What is an antifreeze?</h3>

Anti freeze is a substance that is added in order to prevent a liquid from freezing. An antifreeze is usually an ionic substances that is used during the winter to prevent the freezing of a liquid.

Now;

Forming the equation;

0.75*x+0.5*3=0.6(3+x)

Hence;

0.75*x+1.5=1.8+0.6x

Therefore;

0.75x-0.6x=1.8-1.5

We obtain;

0.15x=0.3

Then;

x=2L

Learn more about antifreeze:brainly.com/question/14789254

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Answer:

see below

Step-by-step explanation:

Part A

Since the lines goes through the point (0,0) the graph is proportional. We can find the rate of change by take the price of corn and dividing by the number of bushels

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Part B

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3 21

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We can find the rate of change for the previous year by using the slope formula

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Fractions

Proper and Improper

Numbers

Least Common Multiple (LCM)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Year 1 water change: $\displaystyle -2 \frac{1}{3}$

Year 2 water change: $\displaystyle -1 \frac{5}{6}$

<u>Step 2: Find Total Water Change</u>

[Set up] Add yearly water changes: $\displaystyle -2 \frac{1}{3} + -1 \frac{5}{6}$
[Fractions] Convert to improper: $\displaystyle \frac{-7}{3} - \frac{11}{6}$
[Fraction] Rewrite [LCM]: $\displaystyle \frac{-14}{6} - \frac{11}{6}$
[Order of Operations] Subtract: $\displaystyle \frac{-25}{6}$
[Fraction] Convert to proper: $\displaystyle -4 \frac{1}{6}$

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