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timofeeve [1]
3 years ago
5

Stuck on this answer have no clue?!

Mathematics
1 answer:
vredina [299]3 years ago
6 0
I think your answer is correct!

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A shop sells chocolate, vanilla and strawberry ice creams. 45% of the ice creams sold are vanilla, and 1/4 are strawberry. What
OverLord2011 [107]

Answer:

30%

Step-by-step explanation:

Well since we know that 45% is vanilla that means we have part of our answer

Also we know we sold 1/4 strawberry which in percent that would be 25%

If we add 45% with 25%  45+25=70 then since something can only be 100%

100%-70%=30%

you sold 30% chocolate

<3  <;

6 0
2 years ago
The difference of 17 and 5 tines a number
emmasim [6.3K]

You can answer this problem in two different ways: the first being (17 - 5) * x, and the second being 12 * x.

6 0
3 years ago
Answer all plz!!! my lil cuzin needs help
Igoryamba

Answer:

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Step-by-step explanation:

YOUR WELCOME (this too forever pls name me brainliest)

6 0
3 years ago
Read 2 more answers
a 18 ft tall statue standing next to a globe casts a 12 ft shadow. Of the globe casts a shadow that is 2 ft ling, then how tall
Igoryamba
<h3>Answer:</h3>

3 ft

<h3>Step-by-step explanation:</h3>

The statue's height is 1.5 times the length of its shadow, so we expect the same relationship for the globe.

... 1.5 × 2 ft = 3 ft

_____

<em>Comment on the problem</em>

As a practical matter, with the sun high enough in the sky to cast a shadow shorter than the object's height, it will be quite difficult to measure the length of the shadow of the point at the top of the globe. The shadow of other parts of the globe will interfere.

4 0
3 years ago
Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by
V125BC [204]
For this case we have the following functions:
 y1 = x + 2&#10;&#10;y2 = x ^ 2 + 2&#10;&#10;y3 = 2 ^ x
 
 When x = 0 we have:
 For y1:
 y1 = 0 + 2&#10;&#10;y1 = 2
 For y2:
 y2 = 0 ^ 2 + 2&#10;&#10;y2 = 0 + 2&#10;&#10;y2 = 2
 Therefore, we have to:
 y1 = y2&#10;

 When x = 5 we have:
 For y2:
 y2 = 5 ^ 2 + 2&#10;&#10;y2 = 25 + 2&#10;&#10;y2 = 27
 For y3:
 y3 = 2 ^ 5&#10;&#10;y3 = 32
 Therefore, we have to:
 y2 \ \textless \ y3&#10;

 When x = -1 we have:
 For y1:
 y1 = -1 + 2&#10;&#10;y1 = 1
 For y2:
 y2 = (-1) ^ 2 + 2&#10;&#10;y2 = 1 + 2&#10;&#10;y2 = 3&#10;
 For y3:
 y3 = 2 ^ {-1}&#10;&#10;y3 = 1/2&#10;&#10;y3 = 0.5
 Therefore, we have to:
 y3 \ \textless \ y1 \ \textless \ y2&#10;

 Answer:
 
When x = 0, y1 = y2
 
When x = 5, y2 <y3
 
When x = -1, y3 <y1 <y2
4 0
3 years ago
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