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Strike441 [17]
2 years ago
6

Abstract Reasoning Classify the angles that result from bisecting each type of angle.

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
6 0

The angles that will be formed when each angle type is bisected can each be classified as:

A. Two acute angles.

B. Two acute angles (45 degrees each).

C. Two acute angles (less than 90 degrees)

D. Two right angles (90 degrees each).

<h3>What are the Measure of the Special Angles?</h3>

An acute angle has a measure that is less than 90 degrees.

A right angle has a measure that is equal to 90 degrees.

The measure of an obtuse angle is equal to an angle measure that is greater than 90 degrees but less than 180 degrees.

The measure of a straight line angles equals 180 degrees.

With the above knowledge, we can determine what type of angle would be formed when each of the angle type is bisected. When an bangle is bisected, it is divided into two equal parts.

A. Bisecting an acute angle will result into two acute angles.

B. Bisecting a right angle will result into two acute angles (45 degrees each).

C. Bisecting an obtuse angle will result into two acute angles (less than 90 degrees)

D. Bisecting an straight angle will result into two right angles (90 degrees each).

Learn more about the angles on:

brainly.com/question/25716982

#SPJ1

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25% Increase

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(5 , -1)

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Step-by-step explanation:

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Choose the statement that describes a way to solve the equation x + 2.5 = 8
scoray [572]

Answer:

subtract 2.5 on both sides

5 0
3 years ago
Can someone please help!!!
RideAnS [48]

Answers:

  • System 1:  x = 3 and y = -5
  • System 2: x = 1 and y = 2

==========================================================

Explanation:

For now, let's focus on system 1.

We have identical copies of "2y" in each equation, which means that if we were to subtract the equations straight down, then the y terms cancel out. That allows us to solve for x.

  • The x terms subtract to 7x-x = 6x
  • The y terms subtract to 0 and go away
  • The right hand sides subtract to 11 minus (-7) = 11-(-7) = 11+7 = 18

After doing those subtractions, we have the new equation 6x = 18 which solves to x = 3. Divide both sides by 6 to isolate x.

Once we know x, we can find out y.

7x+2y = 11

7(3)+2y = 11

21+2y = 11

2y = 11-21

2y = -10

y = -10/2

y = -5

or we can say

x+2y = -7

3+2y = -7

2y = -7-3

2y = -10

y = -10/2

y = -5

We should lead to the same y value either way. This helps confirm we have the correct x value.

Overall, the solution to system 1 is (x,y) = (3, -5)

----------------------------

Now onto system 2.

Unfortunately, we don't have identical y terms this time. But what we can do is double everything in the second equation to go from -x+y = 1 to -2x+2y = 2.

The new equivalent system is

\begin{cases}7x+2y = 11\\-2x+2y = 2\end{cases}

Now we have the same situation as before: Subtract straight down, solve for x.

  • The x terms subtract to 7x-(-2x) = 7x+2x = 9x
  • The y terms go away when subtracting
  • The right hand sides subtract to 11-2 = 9

So we have 9x = 9 and that solves to x = 1.

We'll use this x to find the y value.

7x+2y = 11

7(1)+2y = 11

7+2y = 11

2y = 11-7

2y = 4

y = 4/2

y = 2

Or you could pick on the second equation

-x+y = 1

-1+y = 1

y = 1+1

y = 2

6 0
3 years ago
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