(1.) antelope sprinted the farthest
(2.) cba doing this one lol
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<u><em>The correct answer is: </em></u>C) his solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.
<u><em>Explanation: </em></u><span><u>To solve this rational equation, we cross multiply: </u>
8*(x-4)=2*(x+2).
<u>Using the distributive property, we have </u>
8*x-8*4=2*x+2*2;
8x-32=2x+4.
<u>Subtract 2x from each side: </u>
8x-32-2x=2x+4-2x;
6x-32=4.
<u>Add 32 to each side: </u>
6x-32+32=4+32;
6x=36.
<u>Divide both sides by 6:</u>
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<span><span>=</span></span>

<span><span>;
x=6.
<u>Extraneous solutions</u> are solutions that come about in the problem but are not valid solutions to the problem; the only values of x that would give this sort of answer are -2 and 4, since these are the two values that would make one of the denominators 0 (we cannot divide by 0).</span></span>
Answer:
D. -14
Step-by-step explanation:
The expressions that simplifies to 41 are:
a) 10 + 2³ * 4 - 1
d) 10 + (2³ * 4) - 1
Information about the problem:
a) 10 + 2³ * 4 - 1
b) 10 + 2³ * (4 - 1)
c) (10 + 2³) * 4 - 1
d) 10 + (2³ * 4) - 1
We solve the equations respecting the level of hierarchy:
- First the operations in parentheses, then brackets and finally braces.
- Of the arithmetic operations, first the multiplication and divisions and then the additions and subtractions.
a) 10 + 2³ * 4 - 1
10 + 8*4 - 1
10 + 32 - 1
42 - 1
41 (it applies)
b) 10 + 2³ * (4 - 1)
10 + 8 * (3)
10 + 24
34 (it doesn't applies)
c) (10 + 2³) * 4 - 1
(10 + 8) * 4 - 1
18*4 - 1
72 - 1
71 (it doesn't applies)
d) 10 + (2³ * 4) - 1
10 + (8*4) - 1
10 + 32 -1
42 - 1
41 (it applies)
<h3>What are algebraic operations?</h3>
We can say that they are the set of numbers and symbols that are related by the different mathematical operation signs such as addition, subtraction, multiplication, division among others.
Learn more about algebraic operations at: brainly.com/question/3927786
#SPJ4
Answer:
is this algebra 1
Step-by-step explanation: