A: Package A is a better deal. For example, if you get 5 car washes from each package, the results are $47 for package A and $56 for package B.
B:
Package A: 1-15, 2-1, 3-15, 4-1, 5-15, 6-1, 7-15, 8-1.
Package B: 1-28, 2-7, 3-7, 4-7, 5-7, 6-7, 7-7, 8-7.
C: Graph A represents Geometric growth and Graph B represents Arithmetic growth.
D: Package A
E: Package A
Hope this Helps! Let me know if anything is wrong!
Answer:
![\large\boxed{h\leq-\dfrac{19}{6}\to h\in\left(-\infty,\ -\dfrac{19}{6}\right]}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bh%5Cleq-%5Cdfrac%7B19%7D%7B6%7D%5Cto%20h%5Cin%5Cleft%28-%5Cinfty%2C%5C%20-%5Cdfrac%7B19%7D%7B6%7D%5Cright%5D%7D)
Step-by-step explanation:
Answer:Suppose the cost stock is x and the cost of fund is y.
Total cost of Nora's portfolio:
100x+200y=3800.....i
Total cost of Erin's portfolio
300x+50y=5350...ii
solving the simultaneous equation by elimination method we proceed as follows:
multiplying eqn by 3 and subtracting ii we get:
550y=6050
thus
y=6050/550
y=11
next, multiply ii by 4 and subtracting i we get:
1100x=17600
x=16
thus the cost of Technology stock was $16 and the cost of mutual fund was $11
Step-by-step explanation:
$4.15n - ($250 + $2.45n)
Now that we have our expression, let's set it greater than or equal to 0
$4.15n - ($250 + $2.45n) >= 0
Let's simplify the left side.
$4.15n - $250 - $2.45n >= 0.
Combine like terms.
$1.7n - $250 >= 0
Add $250 to both sides.
$1.7n >= $250
Divide both sides by $1.7
n >= 148
You would need to make 148 light sabers to make a positive profit.
I do not know bro. Have you tried
