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coldgirl [10]
1 year ago
11

Solution set of this equation: 3/X-2 + 2/X+2 = 2 using the general formula please

Mathematics
1 answer:
kumpel [21]1 year ago
5 0

Answer:

Hope ! answer helps you....

You might be interested in
-3(2t-1)=t+t+t+3 pls help
LuckyWell [14K]

Answer:

t=0

Step-by-step explanation:

First, we expand everything. The left-hand side is -3(2t) - 1(-3), and we expand it to be -6t+3. The right-hand side is t+t+t+3, and we can reduce it to 3t+3. Now that we have both sides of the equation, we set them to each other.

-6t+3=3t+3 (subtract 3 on both sides)
-6t=3t (add 6t to both sides)
9t =0 (divide by 9)
t=0

8 0
2 years ago
An architect designs a rectangular flower garden such that the width is exactly​ two-thirds of the length. If 390 feet of antiqu
Ksenya-84 [330]

Length (L): L

width (w): (2/3)L

Perimeter (P) = 2L + 2w

               390 = 2(L) + 2(2/3)(L)

               1170 = 6L + 4L

               1170 = 10L

                  117 = L

width (w): (2/3)L   = (2/3)(117) = 2(39)   = 78

Answer: width = 78 ft, length = 117 ft


3 0
3 years ago
Hank scored 10% extra on his 30 point assignment how many extra points did he earn?
KiRa [710]

Answer:

3

Step-by-step explanation:

10% of 30 = 3

5 0
3 years ago
The area of a rectangular garden is given by the trinomial x2 + x – 42. What are the possible dimensions of the rectangle? Use f
Murrr4er [49]

Answer:

Step-by-step explanation:

Hello, please consider the following.

x^2+x-42\\\\\text{The sum of the zeroes is -1=-7+6 and the product is -42=-7*6.}\\\\\text{So, we can factorise.}\\\\x^2+x-42\\\\=x^2+7x-6x-42\\\\=x(x+7)-6(x+7)\\\\=(x+7)(x-6)

So, the possible dimensions of the rectangle are (x+7) and (x-6).

Thank you.

3 0
4 years ago
Read 2 more answers
Are my answers correct? Precalculus!!
SVETLANKA909090 [29]

Answer:

Unfortunately, your answer is not right.

Step-by-step explanation:

The functions whose graphs do not have asymptotes are the power and the root.

The power function has no asymptote, its domain and rank are all the real.

To verify that the power function does not have an asymptote, let us make the following analysis:

The function y = x ^ n , when x approaches infinity, where does y tend? Of course it tends to infinity as well, therefore it has no horizontal asymptotes (and neither vertical nor oblique)

With respect to the function y= \frac{1}{x} we ​​can verify that if it has asymptote horizontal in y = 0. Since when x approaches infinity the function is closer to the value 0.

For example: 1/2 = 0.5;   1/1000 = 0.001;    1/100000 = 0.00001 and so on. As "x" grows "y" approaches zero

Also, when x approaches 0, the function approaches infinity, in other words, when x tends to 0 y tends to infinity. For example: 1 / 0.5 = 2; 1 / 0.1 = 10; 1 / 0.01 = 100 and so on. This means that the function also has an asymptote at x = 0

6 0
4 years ago
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