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3 years ago

I need help with this math problem. PLEASE!

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

5 0

Answer:

the combined length of the three longest pieces 11/6 units

Step-by-step explanation:

What is the combined length of the three longest pieces?

Given that:

1/3 has 5 x's
1/2 has 4 x's
2/3 has 2 x's

=> the length of the three longest pieces are:

2/3 for the 1st longest length

2/3 for the 2nd longest length

1/2 for the 3rd longest length

=> the combined length of the three longest pieces

= The sum of the 3 lenghts

= 2/3 + 2/3 + 1/2

= 11/6 units

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Please help me with this question!

frez [133]

$\text {Laura = } 12 \text { years } 3 \text { months }$

$\text {Lisa = } 11 \text { years } 7 \text { months }$

$\text {Deborah = } 11 \dfrac{1}{2} \text { years } = 11 \text { years } 6 \text { months }$

$\text {Elizabeth = } 11 \dfrac{1}{3} \text { years } = 11 \text { years } 4 \text { months }$

-----------------------------------------------------
Find Total :
-----------------------------------------------------
$\text {Total = } 12 \text { yr } 3 \text { mth } + 11 \text { yr } 7 \text { mth } + 11 \text { yr} 6 \text { mth} +11 \text { yr } 4 \text { mth}$

$\text {Total = } 45 \text { years } 20 \text { months }$

-----------------------------------------------------
Find Average :
-----------------------------------------------------
$\text {Average = } (45 \text { years } 20 \text { months }) \div 4$

$\text {Average = } 560 \text { months } \div 4$

$\text {Average = } 140 \text { months } \div 4$

$\text {Average = } 11 \text { years } 8 \text { months }$

----------------------------------------------------------------------------------------------------------
$\bf \text {Answer : Average = } 11 \text { years } 8 \text { months }$
----------------------------------------------------------------------------------------------------------

6 0

4 years ago

Need help l don’t understand could someone help me?

alekssr [168]

Answer:

first put the numbers and unknowns to different sides, as in 6x-3x= 14-5, now solve for x, 3x=9, divide each side by 3 to get the value of x, x=3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

An account grows at an annual interest rate of r⁡ ⁣, so it grows by a factor of x=1+r⁡ ⁣⁣ ⁡ each year. The function A(x)=800x

Paladinen [302]

Given:

Annual interest rate = r⁡%

Growth factor : x = 1 + r⁡

The below function gives the amount in the account after 4 years when the growth factor is x⁡ ⁣⁣.

$A(x)=800x^4+350x^3+500x^2+600x$

To find:

The total amount in the account if the interest rate for the account is 3% each year and initial amount.

Solution:

Rate of interest = 3% = 0.03

Growth factor : x = 1 + ⁡0.03 = 1.03

We have,

$A(x)=800x^4+350x^3+500x^2+600x$

Substitute x=1.03 in the given function, to find the total amount in the account if the interest rate for the account is 3% each year.

$A(1.03)=800(1.03)^4+350(1.03)^3+500(1.03)^2+600(1.03)$

$A(1.03)=800(1.12550881)+350(1.092727)+500(1.0609
)+618$

$A(1.03)=900.407048+382.45445+530.45+618$

$A(1.03)=2431.311498
$

$A(1.03)\approx 2431.31
$

Therefore, the total amount in the account is 2431.31 if the interest rate for the account is 3% each year.

For initial amount the rate of interest is 0.

Growth factor : x = 1 + ⁡0 = 1

Substitute x=0 in the given function to find the initial amount.

$A(1)=800(1)^4+350(1)^3+500(1)^2+600(1)$

$A(1)=800+350+500+600$

$A(1)=2250$

Therefore, 2250 was put into the account at the beginning.

3 0

3 years ago

What would be the final balance of an emergency fund containing three to six months’ worth of expenses totaling $4,700 that is h

Nady [450]

Answer:

god be with you

Step-by-step explanation:

6 0

3 years ago

In a certain region, 6% of a city’s population moves to the surrounding suburbs each year, and 4% of the suburban population mov

Charra [1.4K]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Following are the differential equation:

$\to P(C,S)t+1 = P(C,S)t+(- 0.06Ct +0.04St, 0.06Ct - 0.04St ) \ \ \ \\\\or \ \ \ \ \ \ \ \\\\ \to (0.94Ct + 0.04St, 0.96St + 0.06Ct)$

In equation:

$\to t = 0, \ as \ 2019\\\\\to Ct = 10,000,000 \\\\\to St = 800,000,000\\$

$\to P(C, S)1 = (0.94Ct + 0.04St, 0.96St + 0.06Ct) \\\\$

$= (0.94(10000000) + 0.04(800000), 0.96(800000) + 0.06(10000000))\\\\ = (9,400,000 + 32,000), (768,000 +6000000))\\\\ = (9432000, 1368000)$

$\to P(C, S)2 = (0.94(9432000) + 0.04(1368000), 0.96(1368000) + 0.06(9432000))$

$=(8,866,080 + 54,720), (1,313,280 + 565,920)\\\\=(8,920,800, 1,879,200)$

3 0

3 years ago