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Sonbull [250]
3 years ago
15

The ratio of the height to the width of a packaging label is 5 to 19. If the height of the label is 2 inches, what is its width?

HINT: Set up and solve as a proportion and find x.
Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0

Answer:

7.6 inches

Step-by-step explanation:

The ratio of the height to the width of a packaging label is 5 to 19, that is,

h/w = 5/19 [1]

If the height of the label is 2 inches, and its width is unknown (x), that is,

h/w = 2 in/x [2]

We can set up a proportion with [1] and [2],

5/19 = 2 in/x

We use the cross product property of proportions.

5 × x = 19 × 2 in

x = 19 × 2 in/ 5 = 7.6 in

The width is 7.6 inches.

murzikaleks [220]3 years ago
3 0
Height/width=5/19
5/19=2/x
(5)(x)=(19)(2)
5x=38
5/5x=38/5
x=38/5in or 7.6in
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Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

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substitute in the formula

d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}

d=\sqrt{(3)^{2}+(9)^{2}}

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step 2

Find the length side EF

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substitute in the formula

d=\sqrt{(5+3)^{2}+(-2+1)^{2}}

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d_E_F=\sqrt{65}\ units

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D(8,-6) F(-2,5)

substitute in the formula

d=\sqrt{(5+6)^{2}+(-2-8)^{2}}

d=\sqrt{(11)^{2}+(-10)^{2}}

d_D_F=\sqrt{221}\ units

step 4

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we have

d_D_E=\sqrt{90}\ units

d_E_F=\sqrt{65}\ units

d_D_F=\sqrt{221}\ units

so

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

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3 years ago
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