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jeyben [28]
3 years ago
6

Solve pls brainliest

Mathematics
2 answers:
12345 [234]3 years ago
8 0

Answer:

36.5 hours

Step-by-step explanation:

It is 36.5 because 7.3x5 would equal 36.5 which tells you that Salma worked 36.5 hours in the last five days.

Ivahew [28]3 years ago
4 0

Answer:

I'm going to assume that the question is "if Salma worked 7.3 hours each day for the last 5 days how much did she work in total?"

if thats actually the question being asked she worked 36.5 hours

Step-by-step explanation:

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Select a counter-example that makes the conclusion false. 3is prime, 5 is prime, 7 is prime
Butoxors [25]
5^3+7



Hope i helped.
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3 years ago
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Deborah bought a yard of ribbon for $14.76. How much did Deborah pay per inch? (1 yard = 3 fee
natta225 [31]

Answer:

41 cents

Step-by-step explanation:

because their are 36 inches in 1 yard i divided 14.76 by 36 to get the amount she payed per inch.

8 0
3 years ago
7. If -3 < x < 3, determine c and d for the inequality c < 2x + 1 < d
pogonyaev

Answer:

C= -5

D = 7

Step-by-step explanation:

- 3 < x < 3 \\    \\  - 6 < 2x < 6 \\  \\  - 6 + 1 < 2x + 1 < 6 + 1 \\  \\  - 5 < 2x + 1 < 7

6 0
3 years ago
Need help asap important! thanks so much!
a_sh-v [17]

Answer:

You would have $343.37 at the end of the 2 years.

Step-by-step explanation:

Interest earned is like bonus money the bank pays you just for keeping money

\mathrm{Compund\:Interest\:Formula}:\quad A =  P {  \left( 1+ \dfrac{ r  }{ n  }    \right)    }^{ nt  }

P: the starting balance of the account (also called initial deposit, or principal)

A: the new balance in the account after N years.

t: the number of years or time

r: the interest rate, (in decimal form)

n: the number of times the interest is compounded each year.

Annually = each year = 1

P =$300, r = 7%, t = 2, n = 1, A = ?

Substitute the numbers into the "Compound Interest Formula".

A =  300 {  \left( 1+ \dfrac{ 0.07  }{ 1  }    \right)    }^{ 1 \times  2  }

\mathrm{Anything\:divided\:by\:1\:gives\:itself}

A =  300 {  \left( 1+0.07  \right)    }^{ 1 \times  2  }

\mathrm{Add\:1\:and\:0.07\:to\:get\:1.07}

A =  300 \times   { 1.07  }^{ 1 \times  2  }

\mathrm{Multiply\:1\:and\:2\:to\:get\:2}

A =  300 \times   { 1.07  }^{ 2  }

\mathrm{Calculate\:1.07\:to\:the\:power\:of\:2\:and\:get\:1.1449}

A =  300 \times  1.1449

\mathrm{Multiply\:300\:and\:1.1449\:to\:get\:343.47}

A =  343.47

So you would have $343.37 at the end of the 2 years.

Look at the chart

\mathrm{Year}\quad \mathrm{Year\: Interest}\quad \mathrm{Total\:Interest}\quad \mathrm{Balance}\\\quad1\quad\quad\quad $21.00\quad\quad\quad\quad $21.00\quad\quad\quad\quad $321.00\\\quad2\quad\quad\quad $22.47\quad\quad\quad\quad $43.47\quad\quad\quad\quad $343.47

8 0
2 years ago
Each output value is equal to the square of the input value minus<br> five
Ivenika [448]

i think that A pair of an input value and its corresponding output value is called an ordered pair and can be written as (a, b). In an ordered pair the first number, the input a, corresponds to the horizontal axis and the second number, the output b, corresponds to the vertical axis.

We can thus write our values as ordered pairs

(0, 0) - This ordered pair is also referred to as the origin

(1, 2.5)

(2, 5)

(3, 7.5)

These ordered pairs can then be plotted into a graph.

6 0
3 years ago
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