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3 years ago

What ordered pair is a solution of the equation? y=-2x-5

Mathematics

1 answer:

daser333 [38]3 years ago

7 0

Answer:

x=-2.5

Step-by-step explanation:

subsitute y for 0

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A square piece of fabric has an area of 595 cm2.

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To find the length of the side, will take the under root of the area. So, the side will be :

c) 24.4 cm

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3 years ago

Factor 15c·(a+b)+8·(b+a)

AleksAgata [21]

Answer:

(15c + 8)(a + b).

Step-by-step explanation:

15c·(a+b)+8·(b+a)

(a + b) is common to both parts:

= (15c + 8)(a + b).

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2 years ago

18. What is the solution to the system of equations?

AlekseyPX

Answer:

The solution to the system of equation is (0 , -2 , 1).

Step-by-step explanation:

You can check the solutions of the equations by putting the values of x, y, and z one by one.

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2 years ago

Which fraction has the value that's equal to 3/4

mamaluj [8]

One of the fractions that’s equal to $\frac{3}{4}$ is $\frac{12}{16}$

Solution:

Given that , we have to find fractions which has the same value as that of the fraction $\frac{3}{4}$

Now, we know that, there are several fractions with values equal to $\frac{3}{4}$

To find them, just multiply the numerator and denominator by the same number.

$\begin{array}{l}{3 \times 2=6} \\\\ {4 \times 2=8}\end{array}$

Therefore, $\frac{6}{8}$ is equal to $\frac{3}{4}$

We can do the same with 4, to get $\frac{12}{16}$ , or any other number beyond that.

Hence, one of the fractions that’s equal to $\frac{3}{4}$ is $\frac{12}{16}$

4 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have changed the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0

1 year ago