Answer:
<em>3y+5x=6</em>
Step-by-step explanation:
<u>Equation of the Line</u>
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

The line passes through the points (6,-8) and (-3,7), thus:


Simplifying:

Multiplying by 3:


Moving all the variables to the left side:
3y + 5x = 30 - 24
3y + 5x = 6
Answer:
if that statement is true, then DE=ST, and ST=4 so your answer should be <u>DE=4</u>
Explanation:
you can tell that they are even from looking at the first statement, it states <u>DE</u>F=<u>ST</u>U, emphasizing on the DE=ST part, it gives your the answer right there because ST=4
Given:

First, let us find two points from this equation.
We can set values of x and then solve for y.
Let us find the values of y when x = 1, 2, 3, 4, 5

We now have a set of points:
(1, 21)
(2, 16)
(3, 11)
(4, 6)
(5, 1)
Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)
The graph would then look like this:
Given:
A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .
To find:
The fourth-degree polynomial function in factored form.
Solution:
The factor for of nth degree polynomial is:

Where,
are n zeros of the polynomial.
It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:


![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
On further simplification, we get

![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)
Therefore, the required fourth degree polynomial is
.
Answer:
13,600 dollars
Step-by-step explanation:
So if Linda has 20 credit hours in total, and you multiply that by 650 dollars, that will equal 13,000 dollars. If you add 600 (which is the cost of the textbooks for both semesters) to that it will equal 13,600