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2 years ago

Endpoint: (-4, 8), midpoint: (3,-4) Find the other endpoint Explain please

Mathematics

1 answer:

swat322 years ago

4 0

Answer: (10,-16)

Step-by-step explanation:

$A(-4,8)\ \ \ \ C(3,-4)\ \ \ \ \ B(x_B,y_B)=?\\$

See the graph below.

$\displaystyle\\\boxed {x_C=\frac{x_A+x_B}{2} }\\\\$

Multiply both parts of the equation by 2:

$2x_C=x_A+x_B\\2x_C-x_A=x_A+x_B-x_A\\2x_C-x_A=x_B$

Hence,

$x_B=2*3-(-4)\\x_B=6+4\\x_B=10$

$\displaystyle\\\boxed {y_C=\frac{y_A+y_B}{2} }$

Multiply both parts of the equation by 2:

$2y_C=y_A+y_B\\2y_C-y_A=y_A+y_B-y_A\\2y_C-y_A=y_B$

Hence,

$y_B=2*(-4)-8\\y_B=-8-8\\y_B=-16\\Thus,\ B(10,-16)$

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If i walk 4 miles per hour how long would it take to walk 18 miles

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Answer:

18/4 = 4.5

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Step-by-step explanation:

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3 years ago

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Find the midpoint of the segment below and enter its coordinates as an

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Answer:

(-1/2,5)

Step-by-step explanation:

Here is the complete question

Find the midpoint of the segment with endpoints of (1, 4) and (-2, 6) and enter its coordinates as an ordered pair. If necessary, express coordinates as fractions, using the slash mark ( / ) for the fraction bar.

Solution

The mid-point of a line is given by ((x₁ + x₂)/2,(y₁ + y₂)/2). From the question, x₁ = 1, y₁ = 4, x₂ = -2 and y₂ = 6. So,

((x₁ + x₂)/2,(y₁ + y₂)/2) = ((1 + (-2))/2,(4 + 6)/2)

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4 years ago

Simplify the following expression Algebra Fraction

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And whatever you do to the denominator you have to do to the numerator

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3 years ago

A recent college graduate is in the process of deciding which one of three graduate schools he should apply to. He decides to ju

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Answer:

For this case after conduct the ANOVA procedure they got an statistic of:

$F = 8.61$

With a p value of :

$p_v =P(F_{2,15} > 8.61) = 0.003$

Since the p value is lower than the significance level $\alpha=0.1$

We can reject the null hypothesis that the means are equal at the significance level provided.

$t = \frac{\bar X_i -\bar X_j}{s_p \sqrt{\frac{1}{n_i} +\frac{1}{n_j}}}$

For school 1 and 2 we have:

$t = \frac{646.7 -606.7}{52.54 \sqrt{\frac{1}{6} +\frac{1}{6}}}= 1.318$

For school 1 and 3

$t = \frac{646.7 -523.3}{52.54 \sqrt{\frac{1}{6} +\frac{1}{6}}}= 4.068$

For school 2 and 3 we have:

$t = \frac{606.7 -523.3}{52.54 \sqrt{\frac{1}{6} +\frac{1}{6}}}= 2.749$

So as we can see we have significant difference between the means of school 1 and 3, and school 2 and 3

Step-by-step explanation:

Previous concetps

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Solution to the problem

The hypothesis for this case are:

Null hypothesis: $\mu_{1}=\mu_{2}=\mu_{3}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=1,2,3$

If we assume that we have $p$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation: