Answer:
A. The volume of the prism = 204.7 cm³
Step-by-step explanation:
The difficult part is finding the hight x in the triangle with sides 6 6 and 7.
The half of the base of this triangle = 3,5
So we have the right sided triangle with a hypothenusa of 6, one right side of 3,5 and one right side which is x (and is unknown).
Use Pythagoras to find the value of x.
x² + (3,5)² = 6²
x² = 6² - (3,5)²
x² = 36 - 12,25
x² = 23.75
x = +- SQRT(23.75)
{Only the positive part has a meaning.}
x = 4.873
So now it is easy.
The area of the triangle = 3.5 * x
with x = 4.873
The area of the triangle = 3.5 * 4.873
The area of the triangle = 17.06 cm²
The volume of the prism = 12 * the area of the triangle
The volume of the prism = 12 * 17.06
The volume of the prism = 204.67
rounded on 1 decimal.
The volume of the prism = 204.7 cm³
(x+8) - 13 is the answer using x as “number”
Answer:
Part 1
The mistake is Step 2: P + 2·x = 2·y
Part 2
The correct answer is
Step 2 correction: P - 2·x = 2·y
(P - 2·x)/2 = y
Step-by-step explanation:
Part 1
The student's steps are;
Step 1; P = 2·x + 2·y
Step 2: P + 2·x = 2·y
Step 3: P + 2·x/2 = y
The mistake in the work is in Step 2
The mistake is moving 2·x to the left hand side of the equation by adding 2·x to <em>P </em>to get; P + 2·x = 2·y
Part 2
To correct method to move 2·x to the left hand side of the equation, leaving only 2·y on the right hand side is to subtract 2·x from both sides of the equation as follows;
Step 2 correction: P - 2·x = 2·x + 2·y - 2·x = 2·x - 2·x + 2·y = 2·y
∴ P - 2·x = 2·y
(P - 2·x)/2 = y
y = (P - 2·x)/2
Answer:
58
Step-by-step explanation:
As there are 12 teams in the league and each teams plays every other team twice per season. so, the total number of matches in the league will be 132.
let the matches won by home team = 'x'
given,
number of matches drawn = 34
matches won by the away team = x - 18
Now, according to the question,
⇒ total matches = matches drawn + matches won by home team + matches won by away team
⇒ 132 = 34 + x + x -18
⇒ x = 58
79+37=116
180-116=64
Answer- 64